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Line GH contains points [tex]\( G(-2, 6) \)[/tex] and [tex]\( H(5, -3) \)[/tex]. What is the slope of [tex]\( GH \)[/tex]?

A. 6

B. 1

C. 0

D. -1

Sagot :

To find the slope of line GH that passes through points G(-2, 6) and H(5, -3), you use the slope formula. The slope formula is given as:

[tex]\[ \text{slope} = \frac{{y_2 - y_1}}{{x_2 - x_1}} \][/tex]

Here, [tex]\((x_1, y_1)\)[/tex] are the coordinates of point G, and [tex]\((x_2, y_2)\)[/tex] are the coordinates of point H.

1. Identify the coordinates of the points:
- For point G: [tex]\((x_1, y_1) = (-2, 6)\)[/tex]
- For point H: [tex]\((x_2, y_2) = (5, -3)\)[/tex]

2. Substitute these coordinates into the slope formula:

[tex]\[ \text{slope} = \frac{{-3 - 6}}{{5 - (-2)}} \][/tex]

3. Simplify the expression:

[tex]\[ \text{slope} = \frac{{-3 - 6}}{{5 + 2}} \][/tex]
[tex]\[ \text{slope} = \frac{{-9}}{{7}} \][/tex]

4. Perform the division to find the slope in decimal form:

[tex]\[ \text{slope} \approx -1.2857142857142858 \][/tex]

Thus, the slope of the line GH is approximately [tex]\(-1.2857142857142858\)[/tex].