Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Let's analyze the given vector components and calculate their properties. We are given the vector components:
[tex]\[ \mathbf{v} = (r, s, t) = (5, -3, 8) \][/tex]
We'll calculate two main properties: the magnitude of the vector and the direction angle using the components [tex]\( r \)[/tex] and [tex]\( s \)[/tex].
### Step 1: Calculate the Magnitude
The magnitude [tex]\( \|\mathbf{v}\| \)[/tex] of a vector in 3-dimensional space [tex]\(\mathbf{v} = (r, s, t)\)[/tex] is given by the formula:
[tex]\[ \|\mathbf{v}\| = \sqrt{r^2 + s^2 + t^2} \][/tex]
Substituting the given values [tex]\( r = 5 \)[/tex], [tex]\( s = -3 \)[/tex], and [tex]\( t = 8 \)[/tex]:
[tex]\[ \|\mathbf{v}\| = \sqrt{5^2 + (-3)^2 + 8^2} = \sqrt{25 + 9 + 64} = \sqrt{98} \][/tex]
Evaluating [tex]\(\sqrt{98}\)[/tex]:
[tex]\[ \sqrt{98} \approx 9.899 \][/tex]
So, the magnitude of the vector is approximately:
[tex]\[ \|\mathbf{v}\| \approx 9.899 \][/tex]
### Step 2: Calculate the Direction Angle (θ)
The direction angle [tex]\( \theta \)[/tex] in the context of a 3D vector can often be understood as the angle between the projection of the vector on the [tex]\( xy \)[/tex]-plane and the positive [tex]\( x \)[/tex]-axis. This can be calculated as:
[tex]\[ \theta = \arctan\left(\frac{s}{r}\right) \][/tex]
Substituting [tex]\( r = 5 \)[/tex] and [tex]\( s = -3 \)[/tex] into the formula:
[tex]\[ \theta = \arctan\left(\frac{-3}{5}\right) \][/tex]
We convert this angle from radians to degrees:
[tex]\[ \theta \approx -30.964^\circ \][/tex]
So the direction angle is approximately:
[tex]\[ \theta \approx -30.964^\circ \][/tex]
### Consider the Given Options and Find the Closest Match
We compare our calculated magnitude and direction angle to the given options:
1. [tex]\(10.8, \theta = 56.3^\circ\)[/tex]
2. [tex]\(18.4, \theta = 119.4^\circ\)[/tex]
3. [tex]\(41.0, \theta = 77.3^\circ\)[/tex]
4. [tex]\(97.6, \theta = 24.2^\circ\)[/tex]
None of the options match our calculated values ([tex]\(\approx 9.899\)[/tex] for magnitude and [tex]\(-30.964^\circ\)[/tex] for direction). Thus, our result is:
[tex]\[ \rho \approx 9.899, \quad \theta \approx -30.964^\circ \][/tex]
[tex]\[ \mathbf{v} = (r, s, t) = (5, -3, 8) \][/tex]
We'll calculate two main properties: the magnitude of the vector and the direction angle using the components [tex]\( r \)[/tex] and [tex]\( s \)[/tex].
### Step 1: Calculate the Magnitude
The magnitude [tex]\( \|\mathbf{v}\| \)[/tex] of a vector in 3-dimensional space [tex]\(\mathbf{v} = (r, s, t)\)[/tex] is given by the formula:
[tex]\[ \|\mathbf{v}\| = \sqrt{r^2 + s^2 + t^2} \][/tex]
Substituting the given values [tex]\( r = 5 \)[/tex], [tex]\( s = -3 \)[/tex], and [tex]\( t = 8 \)[/tex]:
[tex]\[ \|\mathbf{v}\| = \sqrt{5^2 + (-3)^2 + 8^2} = \sqrt{25 + 9 + 64} = \sqrt{98} \][/tex]
Evaluating [tex]\(\sqrt{98}\)[/tex]:
[tex]\[ \sqrt{98} \approx 9.899 \][/tex]
So, the magnitude of the vector is approximately:
[tex]\[ \|\mathbf{v}\| \approx 9.899 \][/tex]
### Step 2: Calculate the Direction Angle (θ)
The direction angle [tex]\( \theta \)[/tex] in the context of a 3D vector can often be understood as the angle between the projection of the vector on the [tex]\( xy \)[/tex]-plane and the positive [tex]\( x \)[/tex]-axis. This can be calculated as:
[tex]\[ \theta = \arctan\left(\frac{s}{r}\right) \][/tex]
Substituting [tex]\( r = 5 \)[/tex] and [tex]\( s = -3 \)[/tex] into the formula:
[tex]\[ \theta = \arctan\left(\frac{-3}{5}\right) \][/tex]
We convert this angle from radians to degrees:
[tex]\[ \theta \approx -30.964^\circ \][/tex]
So the direction angle is approximately:
[tex]\[ \theta \approx -30.964^\circ \][/tex]
### Consider the Given Options and Find the Closest Match
We compare our calculated magnitude and direction angle to the given options:
1. [tex]\(10.8, \theta = 56.3^\circ\)[/tex]
2. [tex]\(18.4, \theta = 119.4^\circ\)[/tex]
3. [tex]\(41.0, \theta = 77.3^\circ\)[/tex]
4. [tex]\(97.6, \theta = 24.2^\circ\)[/tex]
None of the options match our calculated values ([tex]\(\approx 9.899\)[/tex] for magnitude and [tex]\(-30.964^\circ\)[/tex] for direction). Thus, our result is:
[tex]\[ \rho \approx 9.899, \quad \theta \approx -30.964^\circ \][/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.