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A solution of HCl has [tex]\left[ H^{+} \right] = 0.01 \, \text{M}[/tex]. What is the pH of this solution?

Use [tex]\text{pH} = -\log \left[ H^{+} \right][/tex].

A. -2
B. -1
C. 1
D. 2

Sagot :

To find the pH of the solution of HCl, we start by noting the given concentration of hydrogen ions [tex]\(\left[ H^+ \right] = 0.01 \, M\)[/tex].

The formula to calculate pH is:
[tex]\[ \text{pH} = -\log \left[ H^+ \right] \][/tex]

Substitute the given concentration into the formula:
[tex]\[ \text{pH} = -\log (0.01) \][/tex]

Next, recall that [tex]\(0.01\)[/tex] can be expressed as [tex]\(10^{-2}\)[/tex]. Thus, we have:
[tex]\[ \text{pH} = -\log (10^{-2}) \][/tex]

Using the properties of logarithms, specifically [tex]\(\log (10^x) = x\)[/tex], we find:
[tex]\[ \text{pH} = -(-2) \][/tex]
[tex]\[ \text{pH} = 2 \][/tex]

Therefore, the pH of the solution is:
[tex]\[ \boxed{2} \][/tex]