To determine the probability that a person who is above 35 years old has a hemoglobin level of 9 or above, we need to analyze the data provided in the table and follow these steps:
1. Identify relevant values from the table:
The data concerns three hemoglobin levels ([tex]\(<9\)[/tex], 9-11, and [tex]\(>11\)[/tex]) across three age groups. We are interested in the age group "Above 35 years" and hemoglobin levels of 9 or above.
- Hemoglobin <9: 76 people
- Hemoglobin 9-11: 40 people
- Hemoglobin >11: 162 people
2. Calculate the total number of people above 35 years old:
Adding up the numbers from the above 35-year age group for all hemoglobin levels:
[tex]\[
\text{Total people above 35 years old} = 76 + 40 + 162 = 278
\][/tex]
3. Calculate the number of people above 35 years old with hemoglobin levels 9 or above:
Adding the numbers for those with hemoglobin levels of 9-11 and greater than 11:
[tex]\[
\text{People with hemoglobin } \geq 9 = 40 + 162 = 202
\][/tex]
4. Compute the probability:
Probability is the ratio of the number of people with hemoglobin levels 9 or above to the total number of people above 35 years old. Thus,
[tex]\[
\text{Probability} = \frac{\text{Number of people with hemoglobin levels } \geq 9}{\text{Total number of people above 35 years old}} = \frac{202}{278}
\][/tex]
Given the result:
[tex]\[
\frac{202}{278} \approx 0.7266187050359713
\][/tex]
Therefore, the probability that a person who is above 35 years old has a hemoglobin level of 9 or above is approximately 0.727, which translates to 72.7%. Since this is not one of the answer choices provided, there may have been an error in the printing of the possible answers. The correct computation, however, is approximately 0.727.
