Let’s begin by calculating the total number of orders for each restaurant:
- Restaurant A:
- Accurate orders: 313
- Not accurate orders: 35
- Total orders for Restaurant A: [tex]\(313 + 35 = 348\)[/tex]
- Restaurant B:
- Accurate orders: 277
- Not accurate orders: 56
- Total orders for Restaurant B: [tex]\(277 + 56 = 333\)[/tex]
- Restaurant C:
- Accurate orders: 231
- Not accurate orders: 37
- Total orders for Restaurant C: [tex]\(231 + 37 = 268\)[/tex]
- Restaurant D:
- Accurate orders: 128
- Not accurate orders: 16
- Total orders for Restaurant D: [tex]\(128 + 16 = 144\)[/tex]
Next, we'll find the total number of orders from all restaurants combined:
- Total orders from all restaurants = Total orders from A + Total orders from B + Total orders from C + Total orders from D
- Total orders from all restaurants: [tex]\(348 + 333 + 268 + 144 = 1093\)[/tex]
Then, we'll calculate the total number of orders from restaurants B, C, and D (i.e., orders not from Restaurant A):
- Total orders not from Restaurant A = Total orders from B + Total orders from C + Total orders from D
- Total orders not from Restaurant A: [tex]\(333 + 268 + 144 = 745\)[/tex]
Now, to find the probability of getting food that is not from Restaurant A, we use the ratio of the total number of orders not from Restaurant A to the total number of orders from all restaurants:
[tex]\[
\text{Probability} = \frac{\text{Total orders not from Restaurant A}}{\text{Total orders from all restaurants}} = \frac{745}{1093}
\][/tex]
This simplifies to approximately:
[tex]\[
\text{Probability} \approx 0.682
\][/tex]
Therefore, the probability of getting food that is not from Restaurant A is:
[tex]\[
0.682
\][/tex]
(Rounded to three decimal places as needed.)
