Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Solve for [tex]x[/tex]:

[tex]\[ 3x = 6x - 2 \][/tex]

Sagot :

To solve the equation [tex]\(x^4 - 10x^2 + 4 = 0\)[/tex], let's follow a step-by-step approach:

1. Substitute [tex]\( y = x^2 \)[/tex]: This substitution helps convert the equation from quartic to quadratic.

[tex]\[ x^4 - 10x^2 + 4 = 0 \implies y^2 - 10y + 4 = 0 \][/tex]

2. Solve the quadratic equation [tex]\( y^2 - 10y + 4 = 0 \)[/tex]:

Here, we can use the quadratic formula [tex]\( y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)[/tex]. In this case, [tex]\(a = 1\)[/tex], [tex]\(b = -10\)[/tex], and [tex]\(c = 4\)[/tex]. Plugging in these values:

[tex]\[ y = \frac{10 \pm \sqrt{(-10)^2 - 4 \cdot 1 \cdot 4}}{2 \cdot 1} \][/tex]

Simplify under the square root:

[tex]\[ y = \frac{10 \pm \sqrt{100 - 16}}{2} \][/tex]

[tex]\[ y = \frac{10 \pm \sqrt{84}}{2} \][/tex]

Since [tex]\(\sqrt{84}\)[/tex] can be further simplified:

[tex]\[ y = \frac{10 \pm 2\sqrt{21}}{2} \][/tex]

Divide by 2:

[tex]\[ y = 5 \pm \sqrt{21} \][/tex]

Hence, we have two solutions for [tex]\( y \)[/tex]:

[tex]\[ y_1 = 5 + \sqrt{21} \quad \text{and} \quad y_2 = 5 - \sqrt{21} \][/tex]

3. Re-substitute [tex]\( y = x^2 \)[/tex]: Now we will solve for [tex]\( x \)[/tex] in terms of these results.

For [tex]\( y = 5 + \sqrt{21} \)[/tex]:

[tex]\[ x^2 = 5 + \sqrt{21} \][/tex]

Taking the square root of both sides:

[tex]\[ x = \pm \sqrt{5 + \sqrt{21}} \][/tex]

So, the solutions here are:

[tex]\[ x_1 = \sqrt{5 + \sqrt{21}} \quad \text{and} \quad x_2 = -\sqrt{5 + \sqrt{21}} \][/tex]

For [tex]\( y = 5 - \sqrt{21} \)[/tex]:

[tex]\[ x^2 = 5 - \sqrt{21} \][/tex]

Taking the square root of both sides:

[tex]\[ x = \pm \sqrt{5 - \sqrt{21}} \][/tex]

So, the solutions here are:

[tex]\[ x_3 = \sqrt{5 - \sqrt{21}} \quad \text{and} \quad x_4 = -\sqrt{5 - \sqrt{21}} \][/tex]

4. List all solutions: Collect all the solutions found from both cases.

The roots of the equation [tex]\(x^4 - 10x^2 + 4 = 0\)[/tex] are:

[tex]\[ x = \sqrt{5 + \sqrt{21}}, \quad x = -\sqrt{5 + \sqrt{21}}, \quad x = \sqrt{5 - \sqrt{21}}, \quad \text{and} \quad x = -\sqrt{5 - \sqrt{21}} \][/tex]

Thus, the complete solution set is:

[tex]\[ x = \left\{-\sqrt{5 - \sqrt{21}}, \, \sqrt{5 - \sqrt{21}}, \, -\sqrt{5 + \sqrt{21}}, \, \sqrt{5 + \sqrt{21}}\right\} \][/tex]