Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Which equation is the inverse of [tex]y = 7x^2 - 10[/tex]?

A. [tex]y = \frac{\pm \sqrt{x+10}}{7}[/tex]

B. [tex]y = \pm \sqrt{\frac{x+10}{7}}[/tex]

C. [tex]y = \pm \sqrt{\frac{x}{7} + 10}[/tex]

D. [tex]y = \frac{\pm \sqrt{x}}{7} \pm \frac{\sqrt{10}}{7}[/tex]


Sagot :

To find the inverse of the given equation [tex]\(y = 7x^2 - 10\)[/tex], let's follow the steps in detail:

1. Start with the given equation:
[tex]\[ y = 7x^2 - 10 \][/tex]

2. Swap [tex]\(x\)[/tex] and [tex]\(y\)[/tex]:
Inverse of a function means swapping the roles of [tex]\(x\)[/tex] and [tex]\(y\)[/tex].
[tex]\[ x = 7y^2 - 10 \][/tex]

3. Solve for [tex]\(y\)[/tex]:
Our goal now is to isolate [tex]\(y\)[/tex].

a. Add 10 to both sides to move the constant term to the left side:
[tex]\[ x + 10 = 7y^2 \][/tex]

b. Divide both sides by 7 to isolate the term with [tex]\(y\)[/tex]:
[tex]\[ \frac{x + 10}{7} = y^2 \][/tex]

c. Take the square root of both sides. Remember, taking the square root gives both positive and negative solutions:
[tex]\[ y = \pm \sqrt{\frac{x + 10}{7}} \][/tex]

Therefore, the inverse of the function [tex]\(y = 7x^2 - 10\)[/tex] is:
[tex]\[ y = \pm \sqrt{\frac{x+10}{7}} \][/tex]

The correct answer from the given choices is:
[tex]\[ y = \pm \sqrt{\frac{x+10}{7}} \][/tex]
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.