At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To determine if the equation [tex]\( y = 5x - \square \)[/tex] represents a direct variation, we need to analyze the equation and compare it to the standard form of a direct variation equation.
A direct variation equation has the form:
[tex]\[ y = kx \][/tex]
where [tex]\( k \)[/tex] is a constant.
1. Original Equation:
[tex]\[ y = 5x - \square \][/tex]
2. Condition for Direct Variation:
For the equation to represent a direct variation, the term containing [tex]\(\square\)[/tex] must not alter the direct proportionality between [tex]\( y \)[/tex] and [tex]\( x \)[/tex]. This means the constant term must be zero to match the form [tex]\( y = kx \)[/tex].
3. Substitute 0 in the Box:
If Lydia puts 0 in the box, the equation becomes:
[tex]\[ y = 5x - 0 \][/tex]
which simplifies to:
[tex]\[ y = 5x \][/tex]
4. Analysis of the Modified Equation:
The modified equation [tex]\( y = 5x \)[/tex] is indeed of the form [tex]\( y = kx \)[/tex], where [tex]\( k = 5 \)[/tex]. Therefore, this represents a direct variation.
By comparing the modified equation to the standard form of a direct variation equation, we can conclude:
- If she puts 0 in the box, she would have a direct variation.
Thus, among the provided explanations, "If she puts 0 in the box she would have a direct variation" is the correct explanation.
A direct variation equation has the form:
[tex]\[ y = kx \][/tex]
where [tex]\( k \)[/tex] is a constant.
1. Original Equation:
[tex]\[ y = 5x - \square \][/tex]
2. Condition for Direct Variation:
For the equation to represent a direct variation, the term containing [tex]\(\square\)[/tex] must not alter the direct proportionality between [tex]\( y \)[/tex] and [tex]\( x \)[/tex]. This means the constant term must be zero to match the form [tex]\( y = kx \)[/tex].
3. Substitute 0 in the Box:
If Lydia puts 0 in the box, the equation becomes:
[tex]\[ y = 5x - 0 \][/tex]
which simplifies to:
[tex]\[ y = 5x \][/tex]
4. Analysis of the Modified Equation:
The modified equation [tex]\( y = 5x \)[/tex] is indeed of the form [tex]\( y = kx \)[/tex], where [tex]\( k = 5 \)[/tex]. Therefore, this represents a direct variation.
By comparing the modified equation to the standard form of a direct variation equation, we can conclude:
- If she puts 0 in the box, she would have a direct variation.
Thus, among the provided explanations, "If she puts 0 in the box she would have a direct variation" is the correct explanation.
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.