Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
To determine if the equation [tex]\( y = 5x - \square \)[/tex] represents a direct variation, we need to analyze the equation and compare it to the standard form of a direct variation equation.
A direct variation equation has the form:
[tex]\[ y = kx \][/tex]
where [tex]\( k \)[/tex] is a constant.
1. Original Equation:
[tex]\[ y = 5x - \square \][/tex]
2. Condition for Direct Variation:
For the equation to represent a direct variation, the term containing [tex]\(\square\)[/tex] must not alter the direct proportionality between [tex]\( y \)[/tex] and [tex]\( x \)[/tex]. This means the constant term must be zero to match the form [tex]\( y = kx \)[/tex].
3. Substitute 0 in the Box:
If Lydia puts 0 in the box, the equation becomes:
[tex]\[ y = 5x - 0 \][/tex]
which simplifies to:
[tex]\[ y = 5x \][/tex]
4. Analysis of the Modified Equation:
The modified equation [tex]\( y = 5x \)[/tex] is indeed of the form [tex]\( y = kx \)[/tex], where [tex]\( k = 5 \)[/tex]. Therefore, this represents a direct variation.
By comparing the modified equation to the standard form of a direct variation equation, we can conclude:
- If she puts 0 in the box, she would have a direct variation.
Thus, among the provided explanations, "If she puts 0 in the box she would have a direct variation" is the correct explanation.
A direct variation equation has the form:
[tex]\[ y = kx \][/tex]
where [tex]\( k \)[/tex] is a constant.
1. Original Equation:
[tex]\[ y = 5x - \square \][/tex]
2. Condition for Direct Variation:
For the equation to represent a direct variation, the term containing [tex]\(\square\)[/tex] must not alter the direct proportionality between [tex]\( y \)[/tex] and [tex]\( x \)[/tex]. This means the constant term must be zero to match the form [tex]\( y = kx \)[/tex].
3. Substitute 0 in the Box:
If Lydia puts 0 in the box, the equation becomes:
[tex]\[ y = 5x - 0 \][/tex]
which simplifies to:
[tex]\[ y = 5x \][/tex]
4. Analysis of the Modified Equation:
The modified equation [tex]\( y = 5x \)[/tex] is indeed of the form [tex]\( y = kx \)[/tex], where [tex]\( k = 5 \)[/tex]. Therefore, this represents a direct variation.
By comparing the modified equation to the standard form of a direct variation equation, we can conclude:
- If she puts 0 in the box, she would have a direct variation.
Thus, among the provided explanations, "If she puts 0 in the box she would have a direct variation" is the correct explanation.
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.