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Given that any function of the form [tex]$f(x)=\frac{x+a}{x}$[/tex], where [tex]a[/tex] can be any value, will have an inverse of the form [tex]$f^{-1}(x)=\frac{a}{x-1}$[/tex],

find the inverse of [tex][tex]$f(x)=\frac{x+4}{x}$[/tex][/tex].

Sagot :

To find the inverse of the function [tex]\( f(x) = \frac{x+4}{x} \)[/tex], we need to follow these steps:

1. Express the given function in terms of [tex]\( y \)[/tex]:
Begin by writing the function as an equation where [tex]\( y = f(x) \)[/tex]:
[tex]\[ y = \frac{x+4}{x} \][/tex]

2. Solve for [tex]\( x \)[/tex]:
Rearrange the equation to solve for [tex]\( x \)[/tex] in terms of [tex]\( y \)[/tex]:
[tex]\[ y = \frac{x+4}{x} \][/tex]

Multiply both sides by [tex]\( x \)[/tex] to eliminate the fraction:
[tex]\[ yx = x + 4 \][/tex]

Move all terms involving [tex]\( x \)[/tex] to one side of the equation:
[tex]\[ yx - x = 4 \][/tex]

Factor out [tex]\( x \)[/tex] on the left-hand side:
[tex]\[ x(y-1) = 4 \][/tex]

Solve for [tex]\( x \)[/tex]:
[tex]\[ x = \frac{4}{y-1} \][/tex]

3. Rewrite the inverse function:
Since we originally started with [tex]\( y = f(x) \)[/tex], after solving for [tex]\( x \)[/tex] in terms of [tex]\( y \)[/tex], we now rename [tex]\( y \)[/tex] back to [tex]\( x \)[/tex] to find the inverse function [tex]\( f^{-1}(x) \)[/tex]:

[tex]\[ f^{-1}(x) = \frac{4}{x-1} \][/tex]

Thus, the inverse of the function [tex]\( f(x) = \frac{x+4}{x} \)[/tex] is:

[tex]\[ f^{-1}(x) = \frac{4}{x-1} \][/tex]

This completes our step-by-step solution for finding the inverse of the given function.

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