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What is the solution strength if 30mL of water is added to 20mL of a 1:60 solution? (Write the concentration as a ratio in simplest terms)?

Sagot :

Answer:

Step-by-step explanation:

   derstand the initial concentration:

       A 1:60 solution means 1 part solute in 60 parts total (59 parts solvent + 1 part solute).

       For 20 mL of this solution, the amount of solute can be calculated.

   Calculate the amount of solute in the initial solution:

       The ratio is 1 part solute to 60 parts total solution.

       Thus, in 20 mL of solution, the amount of solute is 160×20601​×20 mL.

   Add water and calculate the new total volume:

       30 mL of water is added to 20 mL of the initial solution.

       The new total volume is 50 mL.

   Determine the new concentration ratio:

       The amount of solute remains the same, but the total volume increases.

Let's go through the calculations:

   Amount of solute in the initial 20 mL solution:

   Amount of solute=160×20=2060=13 mLAmount of solute=601​×20=6020​=31​ mL

   New total volume:

   New total volume=20 mL+30 mL=50 mLNew total volume=20 mL+30 mL=50 mL

   New concentration:

       The amount of solute remains 13 mL31​ mL.

       The new concentration is the ratio of the amount of solute to the total volume.

The new ratio of solute to solution is:

New concentration=13 mL50 mL=13÷50=1150New concentration=50 mL31​ mL​=31​÷50=1501​

So, the new concentration, expressed as a ratio in simplest terms, is:

1:1501:150

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