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Divide [tex]x + 12[/tex] into [tex]x^3 - 2x^2 + 16[/tex].

Sagot :

To divide the polynomial [tex]\( x^3 - 2x^2 + 16 \)[/tex] by [tex]\( x + 2 \)[/tex], we can use polynomial long division. Let me guide you through the long division process step by step.

1. Setup the Division:
Write the dividend [tex]\( x^3 - 2x^2 + 16 \)[/tex] under the long division symbol and the divisor [tex]\( x + 2 \)[/tex] outside.

```
x^2 - 4x + 8
___________________________________________________
x + 2 | x^3 - 2x^2 + 0x + 16
```

2. First Division:
- Divide the leading term of the dividend [tex]\( x^3 \)[/tex] by the leading term of the divisor [tex]\( x \)[/tex], which gives [tex]\( x^2 \)[/tex].
- Multiply the entire divisor [tex]\( x + 2 \)[/tex] by [tex]\( x^2 \)[/tex] and subtract from the original polynomial.
[tex]\[ x^3 - 2x^2 + 0x + 16 - (x^3 + 2x^2) = -4x^2 + 0x + 16 ``` 3. Second Division: - Divide the new dividend's leading term \( -4x^2 \) by the leading term of the divisor \( x \), which gives \( -4x \). - Multiply the entire divisor \( x + 2 \) by \( -4x \) and subtract from the current result. \[ -4x^2 + 0x + 16 - (-4x^2 - 8x) = 8x + 16 ``` 4. Third Division: - Divide the new dividend's leading term \( 8x \) by the leading term of the divisor \( x \), which gives \( 8 \). - Multiply the entire divisor \( x + 2 \) by \( 8 \) and subtract from the current result. \[ 8x + 16 - (8x + 16) = 0 ``` After performing these steps, we arrive at: Quotient: \( x^2 - 4x + 8 \) \ Remainder: \( 0 \) Therefore, the result of dividing \( x^3 - 2x^2 + 16 \) by \( x + 2 \) is: \[ \boxed{(x^2 - 4x + 8, 0)} \][/tex]