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Question 3 of 10

What is the distance between the points (2, 1) and (14, 6) on a coordinate plane?

A. 13 units
B. 12 units
C. 5 units
D. 14 units

Sagot :

To find the distance between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] on a coordinate plane, we use the distance formula:

[tex]\[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]

Given the points [tex]\((2, 1)\)[/tex] and [tex]\((14, 6)\)[/tex], let's identify the coordinates:
- [tex]\((x_1, y_1) = (2, 1)\)[/tex]
- [tex]\((x_2, y_2) = (14, 6)\)[/tex]

Now, apply the coordinates to the distance formula:

1. Compute the difference in the x-coordinates:
[tex]\[ x_2 - x_1 = 14 - 2 = 12 \][/tex]

2. Compute the difference in the y-coordinates:
[tex]\[ y_2 - y_1 = 6 - 1 = 5 \][/tex]

3. Square these differences:
[tex]\[ (12)^2 = 144 \][/tex]
[tex]\[ (5)^2 = 25 \][/tex]

4. Add the squared differences:
[tex]\[ 144 + 25 = 169 \][/tex]

5. Take the square root of the sum:
[tex]\[ \sqrt{169} = 13 \][/tex]

Therefore, the distance between the points [tex]\((2, 1)\)[/tex] and [tex]\((14, 6)\)[/tex] is [tex]\(\boxed{13}\)[/tex] units.

So, the correct answer is:
A. 13 units