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Which two values will make the equation true, for [tex] y \neq 0 [/tex]?

Values: 28, 3, 17, 4, 8, 101

[tex] y \sqrt[3]{6y} - 14 \sqrt[3]{48y} = -11y \sqrt[3]{6y} [/tex]

Sagot :

To solve the equation [tex]\( y \sqrt[3]{6 y} - 14 \sqrt[3]{48 y^{-1}} = -11 y \sqrt[3]{6 y} \)[/tex], we need to identify two specific values that will satisfy the equation:

The equation is:
[tex]\[ y \sqrt[3]{6 y} - 14 \sqrt[3]{48 y^{-1}} = -11 y \sqrt[3]{6 y} \][/tex]

We can rearrange this as:
[tex]\[ y \sqrt[3]{6 y} - 14 \sqrt[3]{48 y^{-1}} + 11 y \sqrt[3]{6 y} = 0 \][/tex]

Combining like terms:
[tex]\[ y \sqrt[3]{6 y} + 11 y \sqrt[3]{6 y} - 14 \sqrt[3]{48 y^{-1}} = 0 \][/tex]

[tex]\[ (1+11) y \sqrt[3]{6 y} - 14 \sqrt[3]{48 y^{-1}} = 0 \][/tex]

[tex]\[ 12 y \sqrt[3]{6 y} - 14 \sqrt[3]{48 y^{-1}} = 0 \][/tex]

Here, the terms we need to balance are:
1. The coefficient with [tex]\( y \sqrt[3]{6 y} \)[/tex]
2. The coefficient with [tex]\( \sqrt[3]{48 y^{-1}} \)[/tex]

For the equation to hold true, the coefficients should be balanced correctly, which happens when:
1. The coefficient with [tex]\( \sqrt[3]{48 y^{-1}} \)[/tex] term is 14.
2. The coefficient with [tex]\( y \sqrt[3]{6 y} \)[/tex] term is 11, which means we multiply it with [tex]\(-1\)[/tex], resulting in [tex]\( -11 \)[/tex].

Given the balancing, the values we need are:
[tex]\[ -11 \ \text{and} \ 14 \][/tex]

These satisfy the equation, and hence,
[tex]\[ y \sqrt[3]{6 y} - 14 \sqrt[3]{48 y^{-1}} = -11 y \sqrt[3]{6 y} \][/tex]

So, the correct values will be 14 and -11.