Answered

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Given the heats of the following reactions:
ДН°(kJ)
1. P4(5) + 6C|2(g) → 4PC|3(g)
-1225.6
11. P4(5) + 502(g) → P4010(5)
-2967.3
III. PC|(g) + Cl2(g) → PC|5(g)
-84.2
PC 3(g) + ½02(g) → C|3PO(g) -285.7
Calculate the value of AH° for the reaction below:
P4010(5) + 6PC15(g) → 10C13PO(g)

Sagot :

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