Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Car traveling at 20 m/s slows at 7 m/s2 how far does the car go before it stops

Sagot :

Answer:

28.57

Explanation:

To find the distance the car travels before it stops, we can use the equations of motion for uniformly decelerated motion.

Given:

- Initial velocity, \( u = 20 \) m/s (since the car is slowing down, we take it as positive)

- Acceleration (deceleration), \( a = -7 \) m/s\(^2\) (negative because it's deceleration)

- Final velocity, \( v = 0 \) m/s (since the car stops)

We need to find the distance \( s \).

The equation relating initial velocity, final velocity, acceleration, and distance is:

\[ v^2 = u^2 + 2as \]

Substitute the given values:

\[ 0 = (20)^2 + 2 \cdot (-7) \cdot s \]

Simplify and solve for \( s \):

\[ 0 = 400 - 14s \]

\[ 14s = 400 \]

\[ s = \frac{400}{14} \]

\[ s = 28.57 \text{ meters} \]

So, the car travels approximately \( 28.57 \) meters before it stops.

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.