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Rachel, Adam, Michelle, Hannah, and James are going to the movies. They have [tex]$65$[/tex] to spend on tickets and snacks. Each movie ticket costs [tex]$9.50$[/tex], and each snack item costs [tex]$4.50$[/tex]. How many snacks can they buy to split among them?

This problem is modeled by the inequality [tex]\( 5(9.5) + 4.5x \leq 65 \)[/tex], which simplifies to [tex]\( 47.5 + 4.5x \leq 65 \)[/tex].

1. The first step in solving the inequality is to subtract 47.5 from both sides.
2. The second step is to divide both sides by 4.5.

How many snacks can they buy to split among them?


Sagot :

Sure, let's solve this step-by-step.

First, let's determine the total cost of the movie tickets for all five people.

1. Calculate the total ticket cost:

Each movie ticket costs \[tex]$9.50, and there are 5 people. \[ \text{Total ticket cost} = 9.50 \times 5 = 47.50 \] So, the total cost for all the tickets is \$[/tex]47.50.

2. Set up and simplify the inequality for snack costs:

We need to account for the cost of snacks within the remaining money. Let [tex]\( x \)[/tex] represent the number of snacks.
The inequality [tex]\( 47.5 + 4.5x \leq 65 \)[/tex] represents the total cost.

Subtract the total ticket cost from the total amount of money available:
[tex]\[ 65 - 47.50 = 17.50 \][/tex]
So, we rewrite the inequality as:
[tex]\[ 4.5x \leq 17.50 \][/tex]

3. Solve for [tex]\( x \)[/tex], the number of snacks:

Divide both sides by 4.5 to isolate [tex]\( x \)[/tex]:
[tex]\[ x \leq \frac{17.50}{4.50} \approx 3.888888888888889 \][/tex]
So, [tex]\( x \approx 3.89 \)[/tex].

This means the maximum number of snacks they can afford is approximately 3.89. Since they cannot buy a fraction of a snack, they can buy 3 snacks and will have a bit of money left over.

Therefore, the friends can buy 3 snacks to share among them.
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