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Sagot :
To determine the frequency of a wave, we can use the relationship between period ([tex]\( T \)[/tex]) and frequency ([tex]\( f \)[/tex]). The frequency is the reciprocal of the period, which can be expressed with the formula:
[tex]\[ f = \frac{1}{T} \][/tex]
Given the period [tex]\( T = 0.008 \)[/tex] seconds, we can calculate the frequency by performing the following steps:
1. Identify the period: The given period [tex]\( T \)[/tex] is 0.008 seconds.
2. Use the formula to find the frequency:
[tex]\[ f = \frac{1}{T} \][/tex]
3. Substitute the value of [tex]\( T \)[/tex] into the formula:
[tex]\[ f = \frac{1}{0.008} \][/tex]
4. Calculate the frequency:
[tex]\[ f = 125 \text{ Hz} \][/tex]
Thus, a wave with a period of 0.008 seconds has a frequency of 125 Hz.
Among the given choices:
A. 80 Hz
B. 12.5 Hz
C. 800 Hz
D. 125 Hz
The correct answer is:
D. 125 Hz.
[tex]\[ f = \frac{1}{T} \][/tex]
Given the period [tex]\( T = 0.008 \)[/tex] seconds, we can calculate the frequency by performing the following steps:
1. Identify the period: The given period [tex]\( T \)[/tex] is 0.008 seconds.
2. Use the formula to find the frequency:
[tex]\[ f = \frac{1}{T} \][/tex]
3. Substitute the value of [tex]\( T \)[/tex] into the formula:
[tex]\[ f = \frac{1}{0.008} \][/tex]
4. Calculate the frequency:
[tex]\[ f = 125 \text{ Hz} \][/tex]
Thus, a wave with a period of 0.008 seconds has a frequency of 125 Hz.
Among the given choices:
A. 80 Hz
B. 12.5 Hz
C. 800 Hz
D. 125 Hz
The correct answer is:
D. 125 Hz.
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