Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

A 25.6 kg box moving on flat ground slows down and comes to a complete stop due to a frictional force.

The coefficient of kinetic friction is 0.124. What is the acceleration of the box?

[tex]\[ a = [?] \, \text{m/s}^2 \][/tex]


Sagot :

To determine the acceleration of the box, we need to follow a series of steps involving the concepts of frictional force and Newton's second law of motion. Here is the detailed step-by-step solution:

### Step 1: Calculate the Normal Force
First, we calculate the normal force acting on the box. On flat ground, the normal force [tex]\( F_N \)[/tex] is equal to the gravitational force acting on the box. This can be calculated using the formula:
[tex]\[ F_N = m \cdot g \][/tex]
where:
- [tex]\( m = 25.6 \)[/tex] kg (mass of the box)
- [tex]\( g = 9.81 \)[/tex] m/s² (acceleration due to gravity)

### Step 2: Normal Force Calculation
[tex]\[ F_N = 25.6 \, \text{kg} \times 9.81 \, \text{m/s}^2 = 251.136 \, \text{N} \][/tex]

### Step 3: Calculate the Frictional Force
Next, we need to calculate the kinetic frictional force [tex]\( F_f \)[/tex]. The frictional force is given by:
[tex]\[ F_f = \mu_k \cdot F_N \][/tex]
where:
- [tex]\( \mu_k = 0.124 \)[/tex] (coefficient of kinetic friction)

### Step 4: Frictional Force Calculation
[tex]\[ F_f = 0.124 \times 251.136 \, \text{N} = 31.140864 \, \text{N} \][/tex]

### Step 5: Determine the Acceleration
Finally, to determine the acceleration [tex]\( a \)[/tex] produced by the frictional force, we use Newton's second law:
[tex]\[ F = m \cdot a \][/tex]
Rearranging for acceleration [tex]\( a \)[/tex]:
[tex]\[ a = \frac{F}{m} \][/tex]
Since this is a deceleration due to friction, the force [tex]\( F \)[/tex] is the frictional force [tex]\( F_f \)[/tex], and it acts in the opposite direction of motion:

### Step 6: Acceleration Calculation
[tex]\[ a = -\frac{31.140864 \, \text{N}}{25.6 \, \text{kg}} = -1.21644 \, \text{m/s}^2 \][/tex]

### Conclusion
Thus, the acceleration of the box is:
[tex]\[ a = -1.21644 \, \text{m/s}^2 \][/tex]
The negative sign indicates that this is a deceleration.
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.