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A triangle was dilated by a scale factor of 2. If [tex]\cos a^{\circ} = \frac{3}{5}[/tex] and [tex]\overline{FD}[/tex] measures 6 units, how long is [tex]\overline{DE}[/tex]?

A. [tex]\overline{DE} = 3.6[/tex] units
B. [tex]\overline{DE} = 8[/tex] units
C. [tex]\overline{DE} = 10[/tex] units
D. [tex]\overline{DE} = 12.4[/tex] units


Sagot :

To find the length of [tex]\(\overline{DE}\)[/tex], given that the triangle was dilated by a scale factor of 2 and [tex]\(\overline{FD}\)[/tex] measures 6 units, you need to apply the property of dilation.

When a geometric figure is dilated by a scale factor, all lengths in the figure are multiplied by that scale factor.

Here’s a step-by-step explanation:

1. The original length of [tex]\(\overline{FD}\)[/tex] is given as 6 units.
2. The dilation process increases all lengths in the figure by the scale factor.

In this problem, the scale factor is 2.

3. To find the new length of [tex]\(\overline{DE}\)[/tex], multiply the original length [tex]\(\overline{FD}\)[/tex] by the scale factor:
[tex]\[ \overline{DE} = \overline{FD} \times \text{scale factor} \][/tex]

4. Substituting the given values:
[tex]\[ \overline{DE} = 6 \, \text{units} \times 2 \][/tex]

5. This calculation gives:
[tex]\[ \overline{DE} = 12 \, \text{units} \][/tex]

Therefore, the length of [tex]\(\overline{DE}\)[/tex] is [tex]\(12\)[/tex] units. The correct answer is:
[tex]\[ \boxed{\overline{DE}=12} \][/tex]
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