Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Let's determine which of the given equations correctly calculates the volume of a sphere with a radius of 4 inches.
The volume [tex]\( V \)[/tex] of a sphere is calculated using the formula:
[tex]\[ V = \frac{4}{3} \pi r^3 \][/tex]
where [tex]\( r \)[/tex] is the radius of the sphere.
Given:
- The radius [tex]\( r = 4 \)[/tex] inches.
First, substitute the given radius into the volume formula:
[tex]\[ V = \frac{4}{3} \pi (4)^3 \][/tex]
Now let's check each of the given equations:
1. [tex]\( V = \frac{4}{3} \pi (4)^3 \)[/tex]
This matches the volume formula and correctly substitutes the radius [tex]\( r \)[/tex] with 4. Let's leave this equation for further evaluation.
2. [tex]\( V = \frac{4}{3} (4)^3 \)[/tex]
This equation is incorrect because it is missing the [tex]\( \pi \)[/tex] term. The volume of a sphere formula must include [tex]\( \pi \)[/tex].
3. [tex]\( V = \frac{2}{3} (8)^3 \)[/tex]
This equation is incorrect because the prefactor should be [tex]\( \frac{4}{3} \)[/tex]. Moreover, [tex]\( (8)^3 \)[/tex] does not reflect the cube of the radius provided, which should be 4.
4. [tex]\( V = \frac{2}{3} \pi (8)^3 \)[/tex]
This equation is incorrect for two reasons. Firstly, the prefactor should be [tex]\( \frac{4}{3} \)[/tex]. Secondly, [tex]\( (8)^3 \)[/tex] doesn't apply since the correct radius provided is 4.
After reviewing all options, the correct equation to find the volume of a sphere with a radius of 4 inches is:
[tex]\[ V = \frac{4}{3} \pi (4)^3 \][/tex]
Therefore, the correct answer is:
[tex]\[ \boxed{V = \frac{4}{3} \pi (4)^3} \][/tex]
The volume [tex]\( V \)[/tex] of a sphere is calculated using the formula:
[tex]\[ V = \frac{4}{3} \pi r^3 \][/tex]
where [tex]\( r \)[/tex] is the radius of the sphere.
Given:
- The radius [tex]\( r = 4 \)[/tex] inches.
First, substitute the given radius into the volume formula:
[tex]\[ V = \frac{4}{3} \pi (4)^3 \][/tex]
Now let's check each of the given equations:
1. [tex]\( V = \frac{4}{3} \pi (4)^3 \)[/tex]
This matches the volume formula and correctly substitutes the radius [tex]\( r \)[/tex] with 4. Let's leave this equation for further evaluation.
2. [tex]\( V = \frac{4}{3} (4)^3 \)[/tex]
This equation is incorrect because it is missing the [tex]\( \pi \)[/tex] term. The volume of a sphere formula must include [tex]\( \pi \)[/tex].
3. [tex]\( V = \frac{2}{3} (8)^3 \)[/tex]
This equation is incorrect because the prefactor should be [tex]\( \frac{4}{3} \)[/tex]. Moreover, [tex]\( (8)^3 \)[/tex] does not reflect the cube of the radius provided, which should be 4.
4. [tex]\( V = \frac{2}{3} \pi (8)^3 \)[/tex]
This equation is incorrect for two reasons. Firstly, the prefactor should be [tex]\( \frac{4}{3} \)[/tex]. Secondly, [tex]\( (8)^3 \)[/tex] doesn't apply since the correct radius provided is 4.
After reviewing all options, the correct equation to find the volume of a sphere with a radius of 4 inches is:
[tex]\[ V = \frac{4}{3} \pi (4)^3 \][/tex]
Therefore, the correct answer is:
[tex]\[ \boxed{V = \frac{4}{3} \pi (4)^3} \][/tex]
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.