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The polynomial p(x)=x^3-7x-6 has a known factor of (x 1). Rewrite p(x) as a product of linear factors

Sagot :

sqdancefan

Answer:

  p(x) = (x +2)(x +1)(x -3)

Step-by-step explanation:

Given p(x) = x³ -7x -6 has a factor of (x +1), you want the function written as a product of linear factors.

Remaining factors

Using synthetic division, we can divide p(x) by (x +1) to find the quadratic factor is (x² -x -6).

  p(x) = (x +1)(x² -x -6)

To factor the quadratic, we note that the factor pairs of -6 are ...

  -6 = -6(1) = -3(2)

The sum of divisors -3 and 2 is -1, so those will be the constants we need for the remaining binomial factors.

  p(x) = (x +1)(x -3)(x +2)

View image sqdancefan
ghanami

Answer:

Step-by-step explanation:

here is an solution :

View image ghanami
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