Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
To make [tex]\( r \)[/tex] the subject of the equation [tex]\( m = \sqrt{\frac{6a + r}{5r}} \)[/tex], follow these steps:
1. Square both sides of the equation to eliminate the square root:
[tex]\[ m^2 = \left(\sqrt{\frac{6a + r}{5r}}\right)^2 \][/tex]
This simplifies to:
[tex]\[ m^2 = \frac{6a + r}{5r} \][/tex]
2. Multiply both sides by [tex]\( 5r \)[/tex] to clear the fraction:
[tex]\[ 5r \cdot m^2 = 6a + r \][/tex]
This can be written as:
[tex]\[ 5m^2r = 6a + r \][/tex]
3. Rearrange the equation to collect all terms involving [tex]\( r \)[/tex] on one side:
[tex]\[ 5m^2r - r = 6a \][/tex]
4. Factor out the common [tex]\( r \)[/tex] on the left-hand side:
[tex]\[ r(5m^2 - 1) = 6a \][/tex]
5. Solve for [tex]\( r \)[/tex] by dividing both sides by [tex]\( 5m^2 - 1 \)[/tex]:
[tex]\[ r = \frac{6a}{5m^2 - 1} \][/tex]
Thus, the expression for [tex]\( r \)[/tex] in terms of [tex]\( m \)[/tex] and [tex]\( a \)[/tex] is:
[tex]\[ r = \frac{6a}{5m^2 - 1} \][/tex]
1. Square both sides of the equation to eliminate the square root:
[tex]\[ m^2 = \left(\sqrt{\frac{6a + r}{5r}}\right)^2 \][/tex]
This simplifies to:
[tex]\[ m^2 = \frac{6a + r}{5r} \][/tex]
2. Multiply both sides by [tex]\( 5r \)[/tex] to clear the fraction:
[tex]\[ 5r \cdot m^2 = 6a + r \][/tex]
This can be written as:
[tex]\[ 5m^2r = 6a + r \][/tex]
3. Rearrange the equation to collect all terms involving [tex]\( r \)[/tex] on one side:
[tex]\[ 5m^2r - r = 6a \][/tex]
4. Factor out the common [tex]\( r \)[/tex] on the left-hand side:
[tex]\[ r(5m^2 - 1) = 6a \][/tex]
5. Solve for [tex]\( r \)[/tex] by dividing both sides by [tex]\( 5m^2 - 1 \)[/tex]:
[tex]\[ r = \frac{6a}{5m^2 - 1} \][/tex]
Thus, the expression for [tex]\( r \)[/tex] in terms of [tex]\( m \)[/tex] and [tex]\( a \)[/tex] is:
[tex]\[ r = \frac{6a}{5m^2 - 1} \][/tex]
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.