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Which sphere has a radius of 4 in.?

A. [tex] V = \frac{32}{3} \pi \text{ in.}^3 [/tex]
B. [tex] V = 36 \pi \text{ in.}^3 [/tex]
C. [tex] V = \frac{256}{3} \pi \text{ in.}^3 [/tex]
D. [tex] V = 288 \pi \text{ in.}^3 [/tex]

Sagot :

To determine which sphere has a radius of 4 inches, we'll use the formula for the volume of a sphere.

The volume [tex]\( V \)[/tex] of a sphere is given by:
[tex]\[ V = \frac{4}{3} \pi r^3 \][/tex]

where [tex]\( r \)[/tex] is the radius of the sphere. Given that the radius [tex]\( r \)[/tex] is 4 inches, we substitute [tex]\( r = 4 \)[/tex] into the formula:

[tex]\[ V = \frac{4}{3} \pi (4)^3 \][/tex]

Calculate [tex]\( 4^3 \)[/tex] (which is 4 cubed):

[tex]\[ 4^3 = 4 \times 4 \times 4 = 64 \][/tex]

Now, substitute [tex]\( 64 \)[/tex] back into the volume equation:

[tex]\[ V = \frac{4}{3} \pi \times 64 \][/tex]

Simplify the multiplication:

[tex]\[ V = \frac{4 \times 64}{3} \pi \][/tex]
[tex]\[ V = \frac{256}{3} \pi \][/tex]

Therefore, the volume of the sphere with a radius of 4 inches is:

[tex]\[ \boxed{\frac{256}{3} \pi} \][/tex]

Given the choices:

1. [tex]\( V = \frac{32}{3} \pi \)[/tex] in[tex]\(^3\)[/tex]
2. [tex]\( V = 36 \pi \)[/tex] in[tex]\(^3\)[/tex]
3. [tex]\( V = \frac{256}{3} \pi \)[/tex] in[tex]\(^3\)[/tex]
4. [tex]\( V = 288 \pi \)[/tex] in[tex]\(^3\)[/tex]

The sphere with the calculated volume [tex]\(\frac{256}{3} \pi\)[/tex] cubic inches matches option 3.

Thus, the sphere with a radius of 4 inches is described by option:

[tex]\[ \boxed{3} \][/tex]