Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
To determine the correct model for predicting the number of toys produced over time given the initial production and the rate of increase, we'll break down the problem step-by-step.
1. Understand the Initial Values and Growth Rate:
- Initial production is [tex]\(1,250,000\)[/tex] toys per year.
- This can be expressed as [tex]\(1.25\)[/tex] million toys, for simplicity in our model.
- The production increases by [tex]\(150\%\)[/tex] each year. A [tex]\(150\%\)[/tex] increase means the production grows to [tex]\(250\%\)[/tex] of the initial value each year because [tex]\(100\% + 150\% = 250\%\)[/tex].
2. Convert the Increase Rate to a Multiplier:
- A [tex]\(250\%\)[/tex] growth means that each year the production is multiplied by [tex]\(2.5\)[/tex].
3. Formulate the Exponential Growth Model:
- The general formula for exponential growth is [tex]\( n(t) = n_0 \cdot a^t \)[/tex] where:
[tex]\( n(t) \)[/tex] is the amount after [tex]\( t \)[/tex] years.
[tex]\( n_0 \)[/tex] is the initial amount.
[tex]\( a \)[/tex] is the growth factor per time period.
[tex]\( t \)[/tex] is the number of time periods (years in this case).
- For this problem:
[tex]\( n_0 = 1.25 \)[/tex] million (the initial production in millions).
The growth factor [tex]\( a = 2.5 \)[/tex].
4. Substitute the Given Values into the Model:
- Replacing [tex]\( n_0 \)[/tex] and [tex]\( a \)[/tex] in the model, we get [tex]\( n(t) = 1.25 \cdot 2.5^t \)[/tex].
5. Check the Options Provided:
- The model [tex]\( n = 1.25 \cdot 2.5^t \)[/tex] matches our derived formula.
Therefore, the correct model to find the number of toys [tex]\( n \)[/tex] (in millions) being produced in [tex]\( t \)[/tex] years is:
[tex]\[ n = 1.25 \cdot 2.5^t \][/tex]
1. Understand the Initial Values and Growth Rate:
- Initial production is [tex]\(1,250,000\)[/tex] toys per year.
- This can be expressed as [tex]\(1.25\)[/tex] million toys, for simplicity in our model.
- The production increases by [tex]\(150\%\)[/tex] each year. A [tex]\(150\%\)[/tex] increase means the production grows to [tex]\(250\%\)[/tex] of the initial value each year because [tex]\(100\% + 150\% = 250\%\)[/tex].
2. Convert the Increase Rate to a Multiplier:
- A [tex]\(250\%\)[/tex] growth means that each year the production is multiplied by [tex]\(2.5\)[/tex].
3. Formulate the Exponential Growth Model:
- The general formula for exponential growth is [tex]\( n(t) = n_0 \cdot a^t \)[/tex] where:
[tex]\( n(t) \)[/tex] is the amount after [tex]\( t \)[/tex] years.
[tex]\( n_0 \)[/tex] is the initial amount.
[tex]\( a \)[/tex] is the growth factor per time period.
[tex]\( t \)[/tex] is the number of time periods (years in this case).
- For this problem:
[tex]\( n_0 = 1.25 \)[/tex] million (the initial production in millions).
The growth factor [tex]\( a = 2.5 \)[/tex].
4. Substitute the Given Values into the Model:
- Replacing [tex]\( n_0 \)[/tex] and [tex]\( a \)[/tex] in the model, we get [tex]\( n(t) = 1.25 \cdot 2.5^t \)[/tex].
5. Check the Options Provided:
- The model [tex]\( n = 1.25 \cdot 2.5^t \)[/tex] matches our derived formula.
Therefore, the correct model to find the number of toys [tex]\( n \)[/tex] (in millions) being produced in [tex]\( t \)[/tex] years is:
[tex]\[ n = 1.25 \cdot 2.5^t \][/tex]
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.