Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Select the correct answer.

What are the zeros of [tex]g(x) = x^3 + 6x^2 - 9x - 54[/tex]?

A. [tex]1, 2, 27[/tex]

B. [tex]3, -3, -6[/tex]

C. [tex]-6, 3, 6[/tex]

D. [tex]2, -1, -18[/tex]


Sagot :

Certainly! Let's find the zeros of the function [tex]\( g(x) = x^3 + 6x^2 - 9x - 54 \)[/tex]. The zeros of a function are the values of [tex]\( x \)[/tex] for which the function equals zero, i.e., [tex]\( g(x) = 0 \)[/tex].

Here's the step-by-step solution:

1. Identify the function:
[tex]\[ g(x) = x^3 + 6x^2 - 9x - 54 \][/tex]

2. Solve the equation [tex]\( g(x) = 0 \)[/tex]:

We need to find the values of [tex]\( x \)[/tex] that satisfy:
[tex]\[ x^3 + 6x^2 - 9x - 54 = 0 \][/tex]

3. Perform the factorization (if possible) or use other algebraic methods to find the roots.

4. List all possible real roots and test them:

For this cubic polynomial, one common method is to use the Rational Root Theorem, which suggests that any rational root of the polynomial [tex]\( P(x) = 0 \)[/tex] is a factor of the constant term (-54) divided by a factor of the leading coefficient (1). Therefore, we test possible integral roots:
[tex]\[ \pm 1, \pm 2, \pm 3, \pm 6, \pm 9, \pm 18, \pm 27, \pm 54 \][/tex]

After verifying, we determine that the roots are [tex]\( 3, -3, -6 \)[/tex].

5. Compare the determined zeros with the given choices:
- Choice A: [tex]\( 1, 2, 27 \)[/tex]
- Choice B: [tex]\( 3, -3, -6 \)[/tex]
- Choice C: [tex]\( -6, 3, 6 \)[/tex]
- Choice D: [tex]\( 2, -1, -18 \)[/tex]

6. Conclusion:
The zeros of the polynomial [tex]\( g(x) = x^3 + 6x^2 - 9x - 54 \)[/tex] are [tex]\( 3, -3, -6 \)[/tex].

Thus, the correct answer is:
[tex]\[ \text{B. } 3, -3, -6 \][/tex]