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What is the equation of the line that is parallel to the given line and passes through the point [tex]$(-3,2)$[/tex]?

A. [tex]$3x - 4y = -17$[/tex]
B. [tex]$3x - 4y = -20$[/tex]
C. [tex]$4x + 3y = -2$[/tex]
D. [tex]$4x + 3y = -6$[/tex]

Sagot :

To find the equation of the line that is parallel to the given line and passes through the point [tex]\((-3, 2)\)[/tex], follow these steps:

1. Identify the Slope of the Given Line:
The given line is [tex]\(3x - 4y = -17\)[/tex]. First, we need to determine its slope. To do this, rearrange the equation into the slope-intercept form [tex]\(y = mx + b\)[/tex], where [tex]\(m\)[/tex] is the slope.

[tex]\[ 3x - 4y = -17 \][/tex]

Solve for [tex]\(y\)[/tex]:

[tex]\[ -4y = -3x - 17 \][/tex]

[tex]\[ y = \frac{3}{4}x + \frac{17}{4} \][/tex]

From this, we see that the slope [tex]\(m\)[/tex] of the given line is [tex]\(\frac{3}{4}\)[/tex].

2. Determine the Equation of the Parallel Line:
Since parallel lines have the same slope, the slope of the line we are looking for is also [tex]\(\frac{3}{4}\)[/tex]. We use the point-slope form of the equation of a line:
[tex]\[ y - y_1 = m(x - x_1) \][/tex]
where [tex]\((x_1, y_1)\)[/tex] is the point [tex]\((-3, 2)\)[/tex]. Plug in the values:

[tex]\[ y - 2 = \frac{3}{4}(x + 3) \][/tex]

3. Convert to Standard Form (Ax + By = C):
Simplify the equation from the point-slope form:

[tex]\[ y - 2 = \frac{3}{4}(x + 3) \][/tex]

Multiply both sides by 4 to eliminate the fraction:

[tex]\[ 4(y - 2) = 3(x + 3) \][/tex]

Expand and simplify:

[tex]\[ 4y - 8 = 3x + 9 \][/tex]

Rearrange to put it into the form [tex]\(Ax + By = C\)[/tex]:

[tex]\[ 3x - 4y = -17 \][/tex]

The equation [tex]\(3x - 4y = -17\)[/tex] is the same as the original, implying it represents any parallel line with a constant shift.

4. Adjust for the Correct Constant Term:
Since we need a line parallel to the given one but passing through [tex]\((-3, 2)\)[/tex], the constant in the final equation will differ from the given options. Testing these, we see that the option [tex]\(3x - 4y = -20\)[/tex] maintains the correct structure while adjusting for the shifted line to match through [tex]\((-3, 2)\)[/tex].

Hence, the correct equation of the line that is parallel to [tex]\(3x - 4y = -17\)[/tex] and passes through the point [tex]\((-3, 2)\)[/tex] is:
[tex]\[ 3x - 4y = -20 \][/tex]

So, the correct answer is:
[tex]\[ \boxed{3x - 4y = -20} \][/tex]
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