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In the reaction [tex]$MgCl_2 + 2 KOH \rightarrow Mg(OH)_2 + 2 KCl$[/tex], how many moles of KOH react with 1 mole of [tex]$MgCl_2$[/tex]?

A. 1
B. 3
C. 2
D. 0.5

Sagot :

GinnyAnswer
To determine how many moles of KOH react with 1 mole of MgCl₂, we need to look at the balanced chemical equation:

[tex]\[ \text{MgCl}_2 + 2 \text{KOH} \rightarrow \text{Mg(OH)}_2 + 2 \text{KCl} \][/tex]

From the balanced equation, we can observe the stoichiometric coefficients in front of each reactant and product. These coefficients indicate the proportion in which the substances react and are produced.

- 1 mole of MgCl₂ reacts with 2 moles of KOH,
- Producing 1 mole of Mg(OH)₂ and 2 moles of KCl.

Therefore, according to the stoichiometric proportions of the reaction, 1 mole of MgCl₂ reacts with 2 moles of KOH.

Given the question and these observations, the correct answer is:

C. 2
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