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Sagot :
Certainly! Let's solve the equation step-by-step.
We are given the equation:
[tex]\[ \frac{x}{2} = 10 \][/tex]
Our goal is to solve for the variable [tex]\( x \)[/tex].
1. To isolate [tex]\( x \)[/tex], we need to get rid of the denominator (which is 2 in this case). To do this, we will multiply both sides of the equation by 2. This step is based on the principle that performing the same operation on both sides of an equation keeps the equation balanced.
2. When we multiply both sides of the equation by 2, it will look like this:
[tex]\[ 2 \cdot \frac{x}{2} = 2 \cdot 10 \][/tex]
3. On the left-hand side, the 2s will cancel each other out since [tex]\( \frac{x \cdot 2}{2} = x \)[/tex].
So after multiplying and simplifying, we get:
[tex]\[ x = 20 \][/tex]
Thus, the solution for the variable [tex]\( x \)[/tex] is:
[tex]\[ x = 20 \][/tex]
We are given the equation:
[tex]\[ \frac{x}{2} = 10 \][/tex]
Our goal is to solve for the variable [tex]\( x \)[/tex].
1. To isolate [tex]\( x \)[/tex], we need to get rid of the denominator (which is 2 in this case). To do this, we will multiply both sides of the equation by 2. This step is based on the principle that performing the same operation on both sides of an equation keeps the equation balanced.
2. When we multiply both sides of the equation by 2, it will look like this:
[tex]\[ 2 \cdot \frac{x}{2} = 2 \cdot 10 \][/tex]
3. On the left-hand side, the 2s will cancel each other out since [tex]\( \frac{x \cdot 2}{2} = x \)[/tex].
So after multiplying and simplifying, we get:
[tex]\[ x = 20 \][/tex]
Thus, the solution for the variable [tex]\( x \)[/tex] is:
[tex]\[ x = 20 \][/tex]
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