Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
To determine which system of linear equations can be solved using the given determinants, we analyze the matrices provided.
We are given:
[tex]\[ \left|A_x\right|=\left|\begin{array}{cc} 20 & -3 \\ -192 & 8 \end{array}\right|, \quad \left|A_y\right|=\left|\begin{array}{cc} 2 & 20 \\ 12 & -192 \end{array}\right| \][/tex]
where [tex]\( A_x \)[/tex] and [tex]\( A_y \)[/tex] are determinants. We aim to identify the corresponding system of linear equations.
First, let's denote the systems of linear equations in question:
1. System 1:
[tex]\[ \begin{cases} 2x - 3y = 20 \\ 12x + 8y = -192 \end{cases} \][/tex]
2. System 2:
[tex]\[ \begin{cases} 20x - 3y = 2 \\ -192x + 8y = 12 \end{cases} \][/tex]
3. System 3:
[tex]\[ \begin{cases} -3x + 2y = 20 \\ 8x + 12y = -192 \end{cases} \][/tex]
4. System 4:
[tex]\[ \begin{cases} -3x + 8y = 20 \end{cases} \][/tex]
We calculate the determinants [tex]\( \left|A_x\right| \)[/tex] and [tex]\( \left|A_y\right| \)[/tex] and compare with given results.
### Determinant [tex]\( \left|A_x\right| \)[/tex]:
[tex]\[ \left|A_x\right| = \begin{vmatrix} 20 & -3 \\ -192 & 8 \end{vmatrix} = (20 \times 8) - (-192 \times -3) = 160 - 576 = -416 \][/tex]
### Determinant [tex]\( \left|A_y\right| \)[/tex]:
[tex]\[ \left|A_y\right| = \begin{vmatrix} 2 & 20 \\ 12 & -192 \end{vmatrix} = (2 \times -192) - (20 \times 12) = -384 - 240 = -624 \][/tex]
The calculated values of the determinants confirm the results:
[tex]\[ \left|A_x\right| = -416 \quad \left|A_y\right| = -624 \][/tex]
Comparing these determinant values with the systems:
- For System 2:
- The first equation [tex]\( 20x - 3y = 2 \)[/tex] forms matrix [tex]\( A_x \)[/tex] with coefficients [tex]\( 20 \)[/tex] and [tex]\(-3\)[/tex].
- The second equation [tex]\( -192x + 8y = 12 \)[/tex] aligns with [tex]\( A_x \)[/tex] as [tex]\( -192 \)[/tex] and [tex]\( 8 \)[/tex].
Thus, the system of linear equations related to the given determinants is:
[tex]\[ \begin{cases} 20x - 3y = 2 \\ -192x + 8y = 12 \end{cases} \][/tex]
This system aligns with the given determinants and their corresponding calculations, confirming that System 2 is the correct set of equations.
We are given:
[tex]\[ \left|A_x\right|=\left|\begin{array}{cc} 20 & -3 \\ -192 & 8 \end{array}\right|, \quad \left|A_y\right|=\left|\begin{array}{cc} 2 & 20 \\ 12 & -192 \end{array}\right| \][/tex]
where [tex]\( A_x \)[/tex] and [tex]\( A_y \)[/tex] are determinants. We aim to identify the corresponding system of linear equations.
First, let's denote the systems of linear equations in question:
1. System 1:
[tex]\[ \begin{cases} 2x - 3y = 20 \\ 12x + 8y = -192 \end{cases} \][/tex]
2. System 2:
[tex]\[ \begin{cases} 20x - 3y = 2 \\ -192x + 8y = 12 \end{cases} \][/tex]
3. System 3:
[tex]\[ \begin{cases} -3x + 2y = 20 \\ 8x + 12y = -192 \end{cases} \][/tex]
4. System 4:
[tex]\[ \begin{cases} -3x + 8y = 20 \end{cases} \][/tex]
We calculate the determinants [tex]\( \left|A_x\right| \)[/tex] and [tex]\( \left|A_y\right| \)[/tex] and compare with given results.
### Determinant [tex]\( \left|A_x\right| \)[/tex]:
[tex]\[ \left|A_x\right| = \begin{vmatrix} 20 & -3 \\ -192 & 8 \end{vmatrix} = (20 \times 8) - (-192 \times -3) = 160 - 576 = -416 \][/tex]
### Determinant [tex]\( \left|A_y\right| \)[/tex]:
[tex]\[ \left|A_y\right| = \begin{vmatrix} 2 & 20 \\ 12 & -192 \end{vmatrix} = (2 \times -192) - (20 \times 12) = -384 - 240 = -624 \][/tex]
The calculated values of the determinants confirm the results:
[tex]\[ \left|A_x\right| = -416 \quad \left|A_y\right| = -624 \][/tex]
Comparing these determinant values with the systems:
- For System 2:
- The first equation [tex]\( 20x - 3y = 2 \)[/tex] forms matrix [tex]\( A_x \)[/tex] with coefficients [tex]\( 20 \)[/tex] and [tex]\(-3\)[/tex].
- The second equation [tex]\( -192x + 8y = 12 \)[/tex] aligns with [tex]\( A_x \)[/tex] as [tex]\( -192 \)[/tex] and [tex]\( 8 \)[/tex].
Thus, the system of linear equations related to the given determinants is:
[tex]\[ \begin{cases} 20x - 3y = 2 \\ -192x + 8y = 12 \end{cases} \][/tex]
This system aligns with the given determinants and their corresponding calculations, confirming that System 2 is the correct set of equations.
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.