Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To determine which system of linear equations can be solved using the given determinants, we analyze the matrices provided.
We are given:
[tex]\[ \left|A_x\right|=\left|\begin{array}{cc} 20 & -3 \\ -192 & 8 \end{array}\right|, \quad \left|A_y\right|=\left|\begin{array}{cc} 2 & 20 \\ 12 & -192 \end{array}\right| \][/tex]
where [tex]\( A_x \)[/tex] and [tex]\( A_y \)[/tex] are determinants. We aim to identify the corresponding system of linear equations.
First, let's denote the systems of linear equations in question:
1. System 1:
[tex]\[ \begin{cases} 2x - 3y = 20 \\ 12x + 8y = -192 \end{cases} \][/tex]
2. System 2:
[tex]\[ \begin{cases} 20x - 3y = 2 \\ -192x + 8y = 12 \end{cases} \][/tex]
3. System 3:
[tex]\[ \begin{cases} -3x + 2y = 20 \\ 8x + 12y = -192 \end{cases} \][/tex]
4. System 4:
[tex]\[ \begin{cases} -3x + 8y = 20 \end{cases} \][/tex]
We calculate the determinants [tex]\( \left|A_x\right| \)[/tex] and [tex]\( \left|A_y\right| \)[/tex] and compare with given results.
### Determinant [tex]\( \left|A_x\right| \)[/tex]:
[tex]\[ \left|A_x\right| = \begin{vmatrix} 20 & -3 \\ -192 & 8 \end{vmatrix} = (20 \times 8) - (-192 \times -3) = 160 - 576 = -416 \][/tex]
### Determinant [tex]\( \left|A_y\right| \)[/tex]:
[tex]\[ \left|A_y\right| = \begin{vmatrix} 2 & 20 \\ 12 & -192 \end{vmatrix} = (2 \times -192) - (20 \times 12) = -384 - 240 = -624 \][/tex]
The calculated values of the determinants confirm the results:
[tex]\[ \left|A_x\right| = -416 \quad \left|A_y\right| = -624 \][/tex]
Comparing these determinant values with the systems:
- For System 2:
- The first equation [tex]\( 20x - 3y = 2 \)[/tex] forms matrix [tex]\( A_x \)[/tex] with coefficients [tex]\( 20 \)[/tex] and [tex]\(-3\)[/tex].
- The second equation [tex]\( -192x + 8y = 12 \)[/tex] aligns with [tex]\( A_x \)[/tex] as [tex]\( -192 \)[/tex] and [tex]\( 8 \)[/tex].
Thus, the system of linear equations related to the given determinants is:
[tex]\[ \begin{cases} 20x - 3y = 2 \\ -192x + 8y = 12 \end{cases} \][/tex]
This system aligns with the given determinants and their corresponding calculations, confirming that System 2 is the correct set of equations.
We are given:
[tex]\[ \left|A_x\right|=\left|\begin{array}{cc} 20 & -3 \\ -192 & 8 \end{array}\right|, \quad \left|A_y\right|=\left|\begin{array}{cc} 2 & 20 \\ 12 & -192 \end{array}\right| \][/tex]
where [tex]\( A_x \)[/tex] and [tex]\( A_y \)[/tex] are determinants. We aim to identify the corresponding system of linear equations.
First, let's denote the systems of linear equations in question:
1. System 1:
[tex]\[ \begin{cases} 2x - 3y = 20 \\ 12x + 8y = -192 \end{cases} \][/tex]
2. System 2:
[tex]\[ \begin{cases} 20x - 3y = 2 \\ -192x + 8y = 12 \end{cases} \][/tex]
3. System 3:
[tex]\[ \begin{cases} -3x + 2y = 20 \\ 8x + 12y = -192 \end{cases} \][/tex]
4. System 4:
[tex]\[ \begin{cases} -3x + 8y = 20 \end{cases} \][/tex]
We calculate the determinants [tex]\( \left|A_x\right| \)[/tex] and [tex]\( \left|A_y\right| \)[/tex] and compare with given results.
### Determinant [tex]\( \left|A_x\right| \)[/tex]:
[tex]\[ \left|A_x\right| = \begin{vmatrix} 20 & -3 \\ -192 & 8 \end{vmatrix} = (20 \times 8) - (-192 \times -3) = 160 - 576 = -416 \][/tex]
### Determinant [tex]\( \left|A_y\right| \)[/tex]:
[tex]\[ \left|A_y\right| = \begin{vmatrix} 2 & 20 \\ 12 & -192 \end{vmatrix} = (2 \times -192) - (20 \times 12) = -384 - 240 = -624 \][/tex]
The calculated values of the determinants confirm the results:
[tex]\[ \left|A_x\right| = -416 \quad \left|A_y\right| = -624 \][/tex]
Comparing these determinant values with the systems:
- For System 2:
- The first equation [tex]\( 20x - 3y = 2 \)[/tex] forms matrix [tex]\( A_x \)[/tex] with coefficients [tex]\( 20 \)[/tex] and [tex]\(-3\)[/tex].
- The second equation [tex]\( -192x + 8y = 12 \)[/tex] aligns with [tex]\( A_x \)[/tex] as [tex]\( -192 \)[/tex] and [tex]\( 8 \)[/tex].
Thus, the system of linear equations related to the given determinants is:
[tex]\[ \begin{cases} 20x - 3y = 2 \\ -192x + 8y = 12 \end{cases} \][/tex]
This system aligns with the given determinants and their corresponding calculations, confirming that System 2 is the correct set of equations.
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.