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Sagot :
To find the value of [tex]\( y \)[/tex] using Cramer's Rule for the given system of linear equations:
[tex]\[ \begin{array}{rcl} 9x - 2y &=& 5 \\ -3x - 4y &=& -4 \end{array} \][/tex]
we proceed with the following steps:
1. Write the coefficient matrix:
[tex]\[ \begin{pmatrix} 9 & -2 \\ -3 & -4 \end{pmatrix} \][/tex]
2. Calculate the determinant of the coefficient matrix:
[tex]\[ \text{det} = \begin{vmatrix} 9 & -2 \\ -3 & -4 \end{vmatrix} = (9 \cdot -4) - (-2 \cdot -3) = -36 - 6 = -42 \][/tex]
3. Construct the matrices required to find [tex]\( y \)[/tex] by replacing the column of [tex]\( y \)[/tex]-coefficients with the constants:
[tex]\[ \text{Matrix for finding } y = \begin{pmatrix} 9 & 5 \\ -3 & -4 \end{pmatrix} \][/tex]
4. Calculate the determinant of this new matrix:
[tex]\[ \text{det}_y = \begin{vmatrix} 9 & 5 \\ -3 & -4 \end{vmatrix} = (9 \cdot -4) - (5 \cdot -3) = -36 + 15 = -21 \][/tex]
5. Find the value of [tex]\( y \)[/tex] using Cramer's Rule which states that [tex]\( y = \frac{\text{det}_y}{\text{det}} \)[/tex]:
[tex]\[ y = \frac{-21}{-42} = \frac{1}{2} \][/tex]
So, the value of [tex]\( y \)[/tex] in the solution to the system of linear equations is [tex]\( \boxed{0.5} \)[/tex].
[tex]\[ \begin{array}{rcl} 9x - 2y &=& 5 \\ -3x - 4y &=& -4 \end{array} \][/tex]
we proceed with the following steps:
1. Write the coefficient matrix:
[tex]\[ \begin{pmatrix} 9 & -2 \\ -3 & -4 \end{pmatrix} \][/tex]
2. Calculate the determinant of the coefficient matrix:
[tex]\[ \text{det} = \begin{vmatrix} 9 & -2 \\ -3 & -4 \end{vmatrix} = (9 \cdot -4) - (-2 \cdot -3) = -36 - 6 = -42 \][/tex]
3. Construct the matrices required to find [tex]\( y \)[/tex] by replacing the column of [tex]\( y \)[/tex]-coefficients with the constants:
[tex]\[ \text{Matrix for finding } y = \begin{pmatrix} 9 & 5 \\ -3 & -4 \end{pmatrix} \][/tex]
4. Calculate the determinant of this new matrix:
[tex]\[ \text{det}_y = \begin{vmatrix} 9 & 5 \\ -3 & -4 \end{vmatrix} = (9 \cdot -4) - (5 \cdot -3) = -36 + 15 = -21 \][/tex]
5. Find the value of [tex]\( y \)[/tex] using Cramer's Rule which states that [tex]\( y = \frac{\text{det}_y}{\text{det}} \)[/tex]:
[tex]\[ y = \frac{-21}{-42} = \frac{1}{2} \][/tex]
So, the value of [tex]\( y \)[/tex] in the solution to the system of linear equations is [tex]\( \boxed{0.5} \)[/tex].
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