Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To graph the function [tex]\(f(x) = 2\left(\frac{1}{2}\right)^{x+2} + 8\)[/tex], let's follow a step-by-step approach to determine its key features and graph it accordingly.
### Step 1: Identify and plot the horizontal asymptote
The function [tex]\(f(x)\)[/tex] has a horizontal asymptote due to the term involving the exponent. As [tex]\(x\)[/tex] approaches positive or negative infinity, the term [tex]\(\left(\frac{1}{2}\right)^{x+2}\)[/tex] approaches 0. Therefore, the horizontal asymptote is determined by the constant term [tex]\(+8\)[/tex].
- Horizontal Asymptote: [tex]\(y = 8\)[/tex]
### Step 2: Calculate and plot points on the function
We choose specific [tex]\(x\)[/tex] values to find points with integer coordinates. It is ideal to pick [tex]\(x\)[/tex] values that result in simpler calculations.
#### Point 1: [tex]\(x = 0\)[/tex]
[tex]\[ f(0) = 2\left(\frac{1}{2}\right)^{0+2} + 8 \][/tex]
[tex]\[ f(0) = 2\left(\frac{1}{2}\right)^2 + 8 \][/tex]
[tex]\[ f(0) = 2 \cdot \frac{1}{4} + 8 \][/tex]
[tex]\[ f(0) = \frac{1}{2} + 8 \][/tex]
[tex]\[ f(0) = 8.5 \][/tex]
The point is [tex]\((0, 8.5)\)[/tex].
#### Point 2: [tex]\(x = 1\)[/tex]
[tex]\[ f(1) = 2\left(\frac{1}{2}\right)^{1+2} + 8 \][/tex]
[tex]\[ f(1) = 2\left(\frac{1}{2}\right)^3 + 8 \][/tex]
[tex]\[ f(1) = 2 \cdot \frac{1}{8} + 8 \][/tex]
[tex]\[ f(1) = \frac{1}{4} + 8 \][/tex]
[tex]\[ f(1) = 8.25 \][/tex]
The point is [tex]\((1, 8.25)\)[/tex].
### Step 3: Plotting the function
1. Plot the horizontal asymptote [tex]\(y = 8\)[/tex]: Draw a dashed line parallel to the x-axis at [tex]\(y = 8\)[/tex].
2. Plot the points [tex]\((0, 8.5)\)[/tex] and [tex]\((1, 8.25)\)[/tex]: Mark these points on the graph.
3. Draw the curve for the function [tex]\(f(x)\)[/tex]: Sketch the curve that passes through the plotted points and approaches the asymptote as [tex]\(x\)[/tex] moves towards positive or negative infinity. The shape should show exponential decay.
【Example Graph】:
y
|
10 + (0, 8.5)
|
9 + (1, 8.25)
8 --+ -------------------------------------------------------- x
|
| Asymptote: [tex]\(y = 8\)[/tex]
|
|
|
This graph efficiently represents the behavior of [tex]\(f(x) = 2\left(\frac{1}{2}\right)^{x+2} + 8\)[/tex], indicating the horizontal asymptote and two critical points with integer coordinates.
### Step 1: Identify and plot the horizontal asymptote
The function [tex]\(f(x)\)[/tex] has a horizontal asymptote due to the term involving the exponent. As [tex]\(x\)[/tex] approaches positive or negative infinity, the term [tex]\(\left(\frac{1}{2}\right)^{x+2}\)[/tex] approaches 0. Therefore, the horizontal asymptote is determined by the constant term [tex]\(+8\)[/tex].
- Horizontal Asymptote: [tex]\(y = 8\)[/tex]
### Step 2: Calculate and plot points on the function
We choose specific [tex]\(x\)[/tex] values to find points with integer coordinates. It is ideal to pick [tex]\(x\)[/tex] values that result in simpler calculations.
#### Point 1: [tex]\(x = 0\)[/tex]
[tex]\[ f(0) = 2\left(\frac{1}{2}\right)^{0+2} + 8 \][/tex]
[tex]\[ f(0) = 2\left(\frac{1}{2}\right)^2 + 8 \][/tex]
[tex]\[ f(0) = 2 \cdot \frac{1}{4} + 8 \][/tex]
[tex]\[ f(0) = \frac{1}{2} + 8 \][/tex]
[tex]\[ f(0) = 8.5 \][/tex]
The point is [tex]\((0, 8.5)\)[/tex].
#### Point 2: [tex]\(x = 1\)[/tex]
[tex]\[ f(1) = 2\left(\frac{1}{2}\right)^{1+2} + 8 \][/tex]
[tex]\[ f(1) = 2\left(\frac{1}{2}\right)^3 + 8 \][/tex]
[tex]\[ f(1) = 2 \cdot \frac{1}{8} + 8 \][/tex]
[tex]\[ f(1) = \frac{1}{4} + 8 \][/tex]
[tex]\[ f(1) = 8.25 \][/tex]
The point is [tex]\((1, 8.25)\)[/tex].
### Step 3: Plotting the function
1. Plot the horizontal asymptote [tex]\(y = 8\)[/tex]: Draw a dashed line parallel to the x-axis at [tex]\(y = 8\)[/tex].
2. Plot the points [tex]\((0, 8.5)\)[/tex] and [tex]\((1, 8.25)\)[/tex]: Mark these points on the graph.
3. Draw the curve for the function [tex]\(f(x)\)[/tex]: Sketch the curve that passes through the plotted points and approaches the asymptote as [tex]\(x\)[/tex] moves towards positive or negative infinity. The shape should show exponential decay.
【Example Graph】:
y
|
10 + (0, 8.5)
|
9 + (1, 8.25)
8 --+ -------------------------------------------------------- x
|
| Asymptote: [tex]\(y = 8\)[/tex]
|
|
|
This graph efficiently represents the behavior of [tex]\(f(x) = 2\left(\frac{1}{2}\right)^{x+2} + 8\)[/tex], indicating the horizontal asymptote and two critical points with integer coordinates.
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.