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If 600 J of work is done in 3 s, what is the power?

(Power: [tex]P = \frac{W}{t}[/tex])

A. 0.005 W
B. 200 W
C. 603 W
D. 1800 W


Sagot :

To calculate the power, we can use the formula:

[tex]\[ P = \frac{W}{t} \][/tex]

where:
- [tex]\( P \)[/tex] is the power,
- [tex]\( W \)[/tex] is the work done,
- [tex]\( t \)[/tex] is the time taken.

Given:
- Work done ([tex]\( W \)[/tex]) = 600 Joules,
- Time taken ([tex]\( t \)[/tex]) = 3 seconds.

Now we can substitute these values into the formula:

[tex]\[ P = \frac{600\ \text{J}}{3\ \text{s}} = 200\ \text{W} \][/tex]

Therefore, the power is:
[tex]\[ 200\ \text{W} \][/tex]

So, the correct answer is:
200 W
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