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Which of the following inequalities is equivalent to the inequality [tex]4x + 4 \leq 9x + 8[/tex]?

A. [tex]x \geq -\frac{4}{5}[/tex]
B. [tex]x \leq -\frac{4}{5}[/tex]
C. [tex]x \geq -\frac{12}{5}[/tex]
D. [tex]x \leq -\frac{12}{5}[/tex]

Answer the question by selecting the correct option.


Sagot :

Let's solve the inequality [tex]\(4x + 4 \leq 9x + 8\)[/tex] step-by-step to understand which of the given options is equivalent to the inequality.

1. Write down the given inequality:
[tex]\[ 4x + 4 \leq 9x + 8 \][/tex]

2. Subtract [tex]\(4x\)[/tex] from both sides to begin isolating the variable [tex]\(x\)[/tex]:
[tex]\[ 4 \leq 5x + 8 \][/tex]

3. Subtract 8 from both sides to further isolate the term with [tex]\(x\)[/tex]:
[tex]\[ 4 - 8 \leq 5x \][/tex]

4. Simplify the left side:
[tex]\[ -4 \leq 5x \][/tex]

5. Divide both sides by 5 to solve for [tex]\(x\)[/tex]:
[tex]\[ -\frac{4}{5} \leq x \][/tex]

This simplifies to:
[tex]\[ x \geq -\frac{4}{5} \][/tex]

So the inequality [tex]\(4x + 4 \leq 9x + 8\)[/tex] is equivalent to [tex]\(x \geq -\frac{4}{5}\)[/tex].

Thus, the correct answer is:
[tex]\[ x \geq -\frac{4}{5} \][/tex]