Certainly! Let's address the problem step by step:
### Step 1: List the scores of both teams
- Team A's scores for three rounds: -40, 10, 0.
- Team B's scores for three rounds: 10, 0, -40.
### Step 2: Calculate the total score for each team
Total score for Team A:
To find the total score, we sum up the scores from each round:
[tex]\[
-40 + 10 + 0 = -30
\][/tex]
So, the total score for Team A is -30.
Total score for Team B:
Similarly, summing the scores for Team B gives us:
[tex]\[
10 + 0 + -40 = -30
\][/tex]
So, the total score for Team B is also -30.
### Step 3: Compare the total scores of Team A and Team B
- Team A's total score: -30
- Team B's total score: -30
Since both teams have the same total score of -30, neither team scored more than the other.
### Conclusion on the scores:
Both teams scored the same.
### Step 4: Discuss adding integers in any order
When we look at the totals calculated for both teams, we observe that the order in which we add integers does not affect the sum. Team A’s scores of -40, 10, and 0 were added in that specific order, while Team B’s scores of 10, 0, and -40 were added in a different order, but both resulted in the same total of -30.
### Final conclusion:
Yes, we can add integers in any order. This is an example of the commutative property of addition, which states that changing the order of addends does not change the sum.
Therefore, the detailed answers are:
- Team A’s total score: -30
- Team B’s total score: -30
- Which team scored more? Neither, both scored the same.
- Can we add integers in any order? Yes, we can add integers in any order.
