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Amy places a bottle of water inside a cooler. As the water cools, its temperature [tex]\( C(t) \)[/tex] in degrees Celsius is given by the following equation, where [tex]\( t \)[/tex] is the number of minutes since the bottle was placed in the cooler.

[tex]\[ C(t) = 4 + 20e^{-0.05t} \][/tex]

Amy wants to drink the water when it reaches a temperature of 21 degrees Celsius. How many minutes should she leave it in the cooler?


Sagot :

To determine how many minutes Amy should leave the bottle of water in the cooler until it reaches a temperature of 21 degrees Celsius, we need to solve the given temperature function for [tex]\( t \)[/tex]. The temperature function is given by:

[tex]\[ C(t) = 4 + 20 e^{-0.05t} \][/tex]

We want to find [tex]\( t \)[/tex] when [tex]\( C(t) = 21 \)[/tex]. So, we set up the equation:

[tex]\[ 21 = 4 + 20 e^{-0.05t} \][/tex]

Next, we solve for [tex]\( t \)[/tex]:

1. Subtract 4 from both sides to isolate the exponential term:
[tex]\[ 21 - 4 = 20 e^{-0.05t} \][/tex]
[tex]\[ 17 = 20 e^{-0.05t} \][/tex]

2. Divide both sides by 20 to further isolate the exponential term:
[tex]\[ \frac{17}{20} = e^{-0.05t} \][/tex]

3. Take the natural logarithm of both sides to solve for the exponent:
[tex]\[ \ln\left(\frac{17}{20}\right) = \ln\left(e^{-0.05t}\right) \][/tex]
[tex]\[ \ln\left(\frac{17}{20}\right) = -0.05t \][/tex]

4. Rearrange to solve for [tex]\( t \)[/tex]:
[tex]\[ t = \frac{\ln\left(\frac{17}{20}\right)}{-0.05} \][/tex]

Using the calculated natural logarithm and performing the division, we find:

[tex]\[ t \approx 3.250378589955499 \][/tex]

Therefore, Amy should leave the bottle in the cooler for approximately [tex]\( 3.25 \)[/tex] minutes until it reaches a temperature of 21 degrees Celsius.
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