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Select the correct answer.

Which property of exponents must be used first to solve this expression?

[tex]\left(x y^2\right)^{\frac{1}{3}}[/tex]

A. [tex](ab)^n = a^n b^n[/tex]

B. [tex]a^m a^n = a^{m+n}[/tex]

C. [tex]\left(\frac{a}{b}\right)^m = \frac{a^m}{b^m}[/tex]

D. [tex]\frac{a^m}{a^m} = a^{m-n}[/tex]


Sagot :

Sure, let's analyze this expression step-by-step.

Given expression:
[tex]\[ \left( x y^2 \right)^{\frac{1}{3}} \][/tex]

We need to determine which property of exponents should be applied first to simplify this expression. Let's examine each property listed:

A. [tex]\((a b)^n = a^n b^n\)[/tex]

This property states that when a product inside parentheses is raised to an exponent, we can distribute the exponent to each factor inside the parentheses.

B. [tex]\(a^m a^n = a^{m+n}\)[/tex]

This property is used when multiplying like bases with different exponents. It combines the exponents by adding them.

C. [tex]\(\left(\frac{a}{b}\right)^m = \frac{a^m}{b^m}\)[/tex]

This property is applied when dividing bases inside parentheses raised to an exponent. We can distribute the exponent to both the numerator and the denominator.

D. [tex]\(\frac{a^m}{a^m} = a^{m-n}\)[/tex]

This property is used when dividing like bases with different exponents. It combines the exponents by subtracting them.

Given our expression, [tex]\(\left( x y^2 \right)^{\frac{1}{3}}\)[/tex], we have a product inside the parentheses that is raised to an exponent.

Applying property (A), we distribute the exponent to each factor in the product:
[tex]\[ (x y^2)^{\frac{1}{3}} = x^{\frac{1}{3}} (y^2)^{\frac{1}{3}} \][/tex]

So, the first property we use is:
A. [tex]\((a b)^n = a^n b^n\)[/tex]

Thus, the correct answer is:
A. [tex]\((a b)^n = a^n b^n\)[/tex]
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