Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
To determine the relative formula mass of the compound [tex]\((NH_4)_3PO_4\)[/tex], we need to follow a step-by-step process:
1. Identify the number of each type of atom in the compound:
- In the compound [tex]\((NH_4)_3PO_4\)[/tex], each [tex]\((NH_4)\)[/tex] unit contains:
- 1 Nitrogen (N) atom
- 4 Hydrogen (H) atoms
- The subscript 3 outside the parentheses indicates there are 3 [tex]\((NH_4)\)[/tex] units, so:
- Number of Nitrogen atoms = 3 units × 1 Nitrogen atom/unit = 3 Nitrogen atoms
- Number of Hydrogen atoms = 3 units × 4 Hydrogen atoms/unit = 12 Hydrogen atoms
- Within the compound formula, [tex]\(PO_4\)[/tex] contains:
- 1 Phosphorus (P) atom
- 4 Oxygen (O) atoms
2. List the atomic masses of each element:
- Nitrogen (N): 14
- Hydrogen (H): 1
- Phosphorus (P): 31
- Oxygen (O): 16
3. Calculate the total mass for each type of atom:
- Total mass of Nitrogen = Number of Nitrogen atoms × Atomic mass of Nitrogen
- Total mass of N = 3 × 14 = 42
- Total mass of Hydrogen = Number of Hydrogen atoms × Atomic mass of Hydrogen
- Total mass of H = 12 × 1 = 12
- Total mass of Phosphorus = Number of Phosphorus atoms × Atomic mass of Phosphorus
- Total mass of P = 1 × 31 = 31
- Total mass of Oxygen = Number of Oxygen atoms × Atomic mass of Oxygen
- Total mass of O = 4 × 16 = 64
4. Sum the masses to get the relative formula mass of [tex]\((NH_4)_3PO_4\)[/tex]:
- Relative formula mass = Total mass of N + Total mass of H + Total mass of P + Total mass of O
- Relative formula mass = 42 + 12 + 31 + 64 = 149
So, the relative formula mass of [tex]\((NH_4)_3PO_4\)[/tex] is 149.
1. Identify the number of each type of atom in the compound:
- In the compound [tex]\((NH_4)_3PO_4\)[/tex], each [tex]\((NH_4)\)[/tex] unit contains:
- 1 Nitrogen (N) atom
- 4 Hydrogen (H) atoms
- The subscript 3 outside the parentheses indicates there are 3 [tex]\((NH_4)\)[/tex] units, so:
- Number of Nitrogen atoms = 3 units × 1 Nitrogen atom/unit = 3 Nitrogen atoms
- Number of Hydrogen atoms = 3 units × 4 Hydrogen atoms/unit = 12 Hydrogen atoms
- Within the compound formula, [tex]\(PO_4\)[/tex] contains:
- 1 Phosphorus (P) atom
- 4 Oxygen (O) atoms
2. List the atomic masses of each element:
- Nitrogen (N): 14
- Hydrogen (H): 1
- Phosphorus (P): 31
- Oxygen (O): 16
3. Calculate the total mass for each type of atom:
- Total mass of Nitrogen = Number of Nitrogen atoms × Atomic mass of Nitrogen
- Total mass of N = 3 × 14 = 42
- Total mass of Hydrogen = Number of Hydrogen atoms × Atomic mass of Hydrogen
- Total mass of H = 12 × 1 = 12
- Total mass of Phosphorus = Number of Phosphorus atoms × Atomic mass of Phosphorus
- Total mass of P = 1 × 31 = 31
- Total mass of Oxygen = Number of Oxygen atoms × Atomic mass of Oxygen
- Total mass of O = 4 × 16 = 64
4. Sum the masses to get the relative formula mass of [tex]\((NH_4)_3PO_4\)[/tex]:
- Relative formula mass = Total mass of N + Total mass of H + Total mass of P + Total mass of O
- Relative formula mass = 42 + 12 + 31 + 64 = 149
So, the relative formula mass of [tex]\((NH_4)_3PO_4\)[/tex] is 149.
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.