A particle moves in one dimensiomal motion through a field for which potential energy of the particle field system is U(x)=A/x^3-B/x where A=0.150eV.nm^3 and B=3.68eV.nm The graph is a potential energy(U)
versus separation(x)
(a). Find the equilibrium position x zero of the particle
(b). Determine the depth U zero of this potential well

Question

13-07-2024
Physics

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A particle moves in one dimensiomal motion through a field for which potential energy of the particle field system is U(x)=A/x^3-B/x where A=0.150eV.nm^3 and B=3.68eV.nm The graph is a potential energy(U)
versus separation(x)
(a). Find the equilibrium position x zero of the particle
(b). Determine the depth U zero of this potential well

Sagot :

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