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Sagot :
To find the [tex]\( y \)[/tex]-intercept of the function [tex]\( g(x) = (x-6)(x-3)(x+2) \)[/tex], we need to determine the value of [tex]\( g(x) \)[/tex] when [tex]\( x = 0 \)[/tex]. The [tex]\( y \)[/tex]-intercept is the value of the function at this point.
Here are the steps:
1. Substitute [tex]\( x = 0 \)[/tex] into the function [tex]\( g(x) = (x-6)(x-3)(x+2) \)[/tex].
[tex]\[ g(0) = (0-6)(0-3)(0+2) \][/tex]
2. Simplify the expression inside the parentheses:
[tex]\[ g(0) = (-6)(-3)(2) \][/tex]
3. Multiply the values together:
[tex]\[ (-6) \times (-3) = 18 \][/tex]
[tex]\[ 18 \times 2 = 36 \][/tex]
Therefore, the [tex]\( y \)[/tex]-intercept of the function [tex]\( g(x) = (x-6)(x-3)(x+2) \)[/tex] is [tex]\( 36 \)[/tex].
In other words, the point where the graph of the function intersects the [tex]\( y \)[/tex]-axis is [tex]\((0, 36)\)[/tex].
Here are the steps:
1. Substitute [tex]\( x = 0 \)[/tex] into the function [tex]\( g(x) = (x-6)(x-3)(x+2) \)[/tex].
[tex]\[ g(0) = (0-6)(0-3)(0+2) \][/tex]
2. Simplify the expression inside the parentheses:
[tex]\[ g(0) = (-6)(-3)(2) \][/tex]
3. Multiply the values together:
[tex]\[ (-6) \times (-3) = 18 \][/tex]
[tex]\[ 18 \times 2 = 36 \][/tex]
Therefore, the [tex]\( y \)[/tex]-intercept of the function [tex]\( g(x) = (x-6)(x-3)(x+2) \)[/tex] is [tex]\( 36 \)[/tex].
In other words, the point where the graph of the function intersects the [tex]\( y \)[/tex]-axis is [tex]\((0, 36)\)[/tex].
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