bhartichhabra1982
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4. The following table shows the points each player scored in four games:

\begin{tabular}{|c|c|c|c|c|}
\hline
PLAYER & GAME 1 & GAME 2 & GAME 3 & GAME 4 \\
\hline
A & 15 & 12 & 8 & Did not play \\
\hline
B & 9 & 16 & 0 & 15 \\
\hline
C & 10 & 0 & 19 & 18 \\
\hline
\end{tabular}

Answer the following questions:

(i) Find the mean to determine A's average number of points scored per game.

(ii) To find the mean number of points per game for C, would you divide the total points by 3 or by 4? Why?

(iii) B played in all four games. How would you find the mean?

(iv) Who is the best performer?

Sagot :

GinnyAnswer
Let's work through the questions step-by-step.

(i) Finding the mean to determine A's average number of points scored per game:
Player A played three games and scored the following points:

- Game 1: 15 points
- Game 2: 12 points
- Game 3: 8 points

To find the mean (average) score for A, sum the points and divide by the number of games played:

[tex]\[ \text{Total points scored by A} = 15 + 12 + 8 = 35 \][/tex]

[tex]\[ \text{Number of games A played} = 3 \][/tex]

[tex]\[ \text{Mean points scored by A per game} = \frac{35}{3} \approx 11.67 \][/tex]

So, A's average number of points scored per game is approximately 11.67 points.

(ii) To find the mean number of points per game for C, would you divide the total points by 3 or by 4? Why?

Player C played in all four games and scored the following points:

- Game 1: 10 points
- Game 2: 0 points
- Game 3: 19 points
- Game 4: 18 points

Since C played in all four games, we need to divide by 4 to find the mean. The total points scored by C is:

[tex]\[ \text{Total points scored by C} = 10 + 0 + 19 + 18 = 47 \][/tex]

[tex]\[ \text{Number of games C played} = 4 \][/tex]

[tex]\[ \text{Mean points scored by C per game} = \frac{47}{4} = 11.75 \][/tex]

Thus, we divide by 4 because C played in all four games. The mean number of points C scored per game is 11.75 points.

(iii) B played in all four games. How would you find the mean?

Player B's points for the four games are as follows:

- Game 1: 9 points
- Game 2: 16 points
- Game 3: 0 points
- Game 4: 15 points

To calculate the mean, sum the points and divide by the number of games:

[tex]\[ \text{Total points scored by B} = 9 + 16 + 0 + 15 = 40 \][/tex]

[tex]\[ \text{Number of games B played} = 4 \][/tex]

[tex]\[ \text{Mean points scored by B per game} = \frac{40}{4} = 10 \][/tex]

So, B's average number of points scored per game is 10 points.

Who is the best performer?

We compare the mean points scored per game by each player:

- A: 11.67 points per game
- B: 10 points per game
- C: 11.75 points per game

The highest mean points per game is 11.75, which belongs to Player C.

Therefore, the best performer is Player C.
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