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Sagot :
Let's determine if any three numbers from the set {1, 6, 7, 3, 2} can add up to 12.
First, we need to consider all possible combinations of three numbers from this set and check their sums. Here are the combinations:
1. [tex]\(1 + 6 + 7\)[/tex]
2. [tex]\(1 + 6 + 3\)[/tex]
3. [tex]\(1 + 6 + 2\)[/tex]
4. [tex]\(1 + 7 + 3\)[/tex]
5. [tex]\(1 + 7 + 2\)[/tex]
6. [tex]\(1 + 3 + 2\)[/tex]
7. [tex]\(6 + 7 + 3\)[/tex]
8. [tex]\(6 + 7 + 2\)[/tex]
9. [tex]\(6 + 3 + 2\)[/tex]
10. [tex]\(7 + 3 + 2\)[/tex]
Now, let's find the sums:
1. [tex]\(1 + 6 + 7 = 14\)[/tex]
2. [tex]\(1 + 6 + 3 = 10\)[/tex]
3. [tex]\(1 + 6 + 2 = 9\)[/tex]
4. [tex]\(1 + 7 + 3 = 11\)[/tex]
5. [tex]\(1 + 7 + 2 = 10\)[/tex]
6. [tex]\(1 + 3 + 2 = 6\)[/tex]
7. [tex]\(6 + 7 + 3 = 16\)[/tex]
8. [tex]\(6 + 7 + 2 = 15\)[/tex]
9. [tex]\(6 + 3 + 2 = 11\)[/tex]
10. [tex]\(7 + 3 + 2 = 12\)[/tex]
We can observe that the combination [tex]\(7 + 3 + 2\)[/tex] adds up to 12.
Therefore, the answer is Yes: Three of the given numbers do add up to 12.
First, we need to consider all possible combinations of three numbers from this set and check their sums. Here are the combinations:
1. [tex]\(1 + 6 + 7\)[/tex]
2. [tex]\(1 + 6 + 3\)[/tex]
3. [tex]\(1 + 6 + 2\)[/tex]
4. [tex]\(1 + 7 + 3\)[/tex]
5. [tex]\(1 + 7 + 2\)[/tex]
6. [tex]\(1 + 3 + 2\)[/tex]
7. [tex]\(6 + 7 + 3\)[/tex]
8. [tex]\(6 + 7 + 2\)[/tex]
9. [tex]\(6 + 3 + 2\)[/tex]
10. [tex]\(7 + 3 + 2\)[/tex]
Now, let's find the sums:
1. [tex]\(1 + 6 + 7 = 14\)[/tex]
2. [tex]\(1 + 6 + 3 = 10\)[/tex]
3. [tex]\(1 + 6 + 2 = 9\)[/tex]
4. [tex]\(1 + 7 + 3 = 11\)[/tex]
5. [tex]\(1 + 7 + 2 = 10\)[/tex]
6. [tex]\(1 + 3 + 2 = 6\)[/tex]
7. [tex]\(6 + 7 + 3 = 16\)[/tex]
8. [tex]\(6 + 7 + 2 = 15\)[/tex]
9. [tex]\(6 + 3 + 2 = 11\)[/tex]
10. [tex]\(7 + 3 + 2 = 12\)[/tex]
We can observe that the combination [tex]\(7 + 3 + 2\)[/tex] adds up to 12.
Therefore, the answer is Yes: Three of the given numbers do add up to 12.
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