At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Questions:

(a) [tex]O(2,2)[/tex], [tex]A(5,4)[/tex], and [tex]B(-1,4)[/tex] are three points. Show that [tex]OA = OB[/tex].

Sagot :

Certainly! Let's solve the problem step-by-step to demonstrate that the distance between point [tex]\(O(2, 2)\)[/tex] and point [tex]\(A(5, 4)\)[/tex] is equal to the distance between point [tex]\(O(2, 2)\)[/tex] and point [tex]\(B(-1, 4)\)[/tex].

### Step-by-Step Solution:

#### (a) Calculate the distance [tex]\(OA\)[/tex] between points [tex]\(O\)[/tex] and [tex]\(A\)[/tex]:

Points:
[tex]\( O = (2, 2) \)[/tex]
[tex]\( A = (5, 4) \)[/tex]

The distance formula between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is:
[tex]\[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]

Using the coordinates of [tex]\(O\)[/tex] and [tex]\(A\)[/tex]:
[tex]\[ OA = \sqrt{(5 - 2)^2 + (4 - 2)^2} \][/tex]

Calculate the differences:
[tex]\[ x\text{-difference} = 5 - 2 = 3 \][/tex]
[tex]\[ y\text{-difference} = 4 - 2 = 2 \][/tex]

Square these differences:
[tex]\[ x\text{-difference squared} = 3^2 = 9 \][/tex]
[tex]\[ y\text{-difference squared} = 2^2 = 4 \][/tex]

Add these squares and take the square root:
[tex]\[ OA = \sqrt{9 + 4} = \sqrt{13} \approx 3.605551275463989 \][/tex]

#### (b) Calculate the distance [tex]\(OB\)[/tex] between points [tex]\(O\)[/tex] and [tex]\(B\)[/tex]:

Points:
[tex]\( O = (2, 2) \)[/tex]
[tex]\( B = (-1, 4) \)[/tex]

Using the coordinates of [tex]\(O\)[/tex] and [tex]\(B\)[/tex]:
[tex]\[ OB = \sqrt{(-1 - 2)^2 + (4 - 2)^2} \][/tex]

Calculate the differences:
[tex]\[ x\text{-difference} = -1 - 2 = -3 \][/tex]
[tex]\[ y\text{-difference} = 4 - 2 = 2 \][/tex]

Square these differences:
[tex]\[ x\text{-difference squared} = (-3)^2 = 9 \][/tex]
[tex]\[ y\text{-difference squared} = 2^2 = 4 \][/tex]

Add these squares and take the square root:
[tex]\[ OB = \sqrt{9 + 4} = \sqrt{13} \approx 3.605551275463989 \][/tex]

#### (c) Compare the distances [tex]\(OA\)[/tex] and [tex]\(OB\)[/tex]:

We have:
[tex]\[ OA \approx 3.605551275463989 \][/tex]
[tex]\[ OB \approx 3.605551275463989 \][/tex]

Therefore, we can conclude:
[tex]\[ OA = OB \][/tex]

Hence, the distances from point [tex]\(O\)[/tex] to points [tex]\(A\)[/tex] and [tex]\(B\)[/tex] are equal.