Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

How would you find the zero of f (x)=16x^4 - 9x^2

Sagot :

Lilith
[tex] f (x) = 16x ^ 4 - 9x ^ 2 \\ \\16x ^ 4 - 9x ^ 2=0\\ \\x^2(16x^2-9)=0 \\ \\x^2 =0 \ \ or \ \ 16x^2-9=0\\ \\ x=0 \ \ or \ \ (4x-3)(4x+3)=0\\ \\ x=0 \ \ or \ \ 4x-3=0 \ \ or \ \ 4x+3 =0\\ \\x=0 \ \ or \ \ 4x=3 \ \ / :4 \ \ or \ \ 4x=-3\ \ / :4 \\ \\ x=0 \ \ or \ \ x=\frac{3}{4} \ \ or \ \ x=-\frac{3}{4} [/tex]
[tex]f(x)=16x^4-9x^2\\\\f(x)=0\iff16x^4-9x^2=0\\\\x^2(16x^2-9)=0\iff x^2=0\ \vee\ 16x^2-9=0\\\\x=0\ \vee\ 16x^2=9\\\\x=0\ \vee\ x^2=\frac{9}{16}\\\\x=0\ \vee\ x=-\sqrt\frac{9}{16}\ \vee\ x=\sqrt\frac{9}{16}\\\\x=0\ \vee\ x=-\frac{3}{4}\ \vee\ x=\frac{3}{4}[/tex]
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.