Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To determine the number of atoms of Bismuth (Bi) in a 41.8-gram sample, we need to follow these steps:
1. Determine the molar mass of Bismuth (Bi):
- The molar mass of Bismuth (Bi) is given as 208.98 grams per mole (g/mol).
2. Calculate the number of moles of Bi:
- To calculate the number of moles, we use the formula:
[tex]\[ \text{moles of Bi} = \frac{\text{mass of the sample}}{\text{molar mass of Bi}} \][/tex]
- Given:
[tex]\[ \text{mass of the sample} = 41.8 \text{ grams} \][/tex]
[tex]\[ \text{molar mass of Bi} = 208.98 \text{ g/mol} \][/tex]
- Substituting these values into the formula:
[tex]\[ \text{moles of Bi} = \frac{41.8 \text{ grams}}{208.98 \text{ g/mol}} \approx 0.20001914058761602 \text{ moles} \][/tex]
3. Use Avogadro's Number to calculate the number of atoms of Bi:
- Avogadro's Number is given as [tex]\(6.022 \times 10^{23}\)[/tex] atoms per mole.
- To find the number of atoms, we multiply the number of moles by Avogadro's Number:
[tex]\[ \text{number of atoms of Bi} = \text{moles of Bi} \times \text{Avogadro's Number} \][/tex]
- Substituting the values:
[tex]\[ \text{number of atoms of Bi} = 0.20001914058761602 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mole} \approx 1.2045152646186236 \times 10^{23} \text{ atoms} \][/tex]
Therefore, in a 41.8 gram sample of Bismuth, there are approximately [tex]\(1.2045152646186236 \times 10^{23}\)[/tex] atoms of Bi.
1. Determine the molar mass of Bismuth (Bi):
- The molar mass of Bismuth (Bi) is given as 208.98 grams per mole (g/mol).
2. Calculate the number of moles of Bi:
- To calculate the number of moles, we use the formula:
[tex]\[ \text{moles of Bi} = \frac{\text{mass of the sample}}{\text{molar mass of Bi}} \][/tex]
- Given:
[tex]\[ \text{mass of the sample} = 41.8 \text{ grams} \][/tex]
[tex]\[ \text{molar mass of Bi} = 208.98 \text{ g/mol} \][/tex]
- Substituting these values into the formula:
[tex]\[ \text{moles of Bi} = \frac{41.8 \text{ grams}}{208.98 \text{ g/mol}} \approx 0.20001914058761602 \text{ moles} \][/tex]
3. Use Avogadro's Number to calculate the number of atoms of Bi:
- Avogadro's Number is given as [tex]\(6.022 \times 10^{23}\)[/tex] atoms per mole.
- To find the number of atoms, we multiply the number of moles by Avogadro's Number:
[tex]\[ \text{number of atoms of Bi} = \text{moles of Bi} \times \text{Avogadro's Number} \][/tex]
- Substituting the values:
[tex]\[ \text{number of atoms of Bi} = 0.20001914058761602 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mole} \approx 1.2045152646186236 \times 10^{23} \text{ atoms} \][/tex]
Therefore, in a 41.8 gram sample of Bismuth, there are approximately [tex]\(1.2045152646186236 \times 10^{23}\)[/tex] atoms of Bi.
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.