Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Two teams are pulling a heavy chest located at point [tex]$X$[/tex]. The teams are 4.6 meters away from each other. Team [tex]$A$[/tex] is 2.4 meters away from the chest, and Team [tex]$B$[/tex] is 3.2 meters away. Their ropes are attached at an angle of [tex]$110^{\circ}$[/tex].

Law of Sines: [tex]$\frac{\sin (A)}{a}=\frac{\sin (B)}{b}=\frac{\sin (C)}{c}$[/tex]

Which equation can be used to solve for angle [tex]$A$[/tex]?

A. [tex]$\frac{\sin (A)}{2.4}=\frac{\sin \left(110^{\circ}\right)}{4.6}$[/tex]

B. [tex]$\frac{\sin (A)}{4.6}=\frac{\sin \left(110^{\circ}\right)}{2.4}$[/tex]

C. [tex]$\frac{\sin (A)}{3.2}=\frac{\sin \left(110^{\circ}\right)}{4.6}$[/tex]

D. [tex]$\frac{\sin (A)}{4.6}=\frac{\sin \left(110^{\circ}\right)}{3.2}$[/tex]


Sagot :

To solve for angle [tex]\( A \)[/tex] using the Law of Sines, we can follow these steps:

1. Identify the given values:
- Distance from Team A to the chest ([tex]\(a\)[/tex]): [tex]\(2.4\)[/tex] meters
- Distance from Team B to the chest ([tex]\(b\)[/tex]): [tex]\(3.2\)[/tex] meters
- Distance between the teams ([tex]\(c\)[/tex]): [tex]\(4.6\)[/tex] meters
- Angle opposite to side [tex]\(c\)[/tex]: [tex]\(\angle C = 110^\circ\)[/tex]

2. Write the Law of Sines formula:
The Law of Sines states that:
[tex]\[ \frac{\sin (A)}{a} = \frac{\sin (B)}{b} = \frac{\sin (C)}{c} \][/tex]

3. Substitute the given values into the Law of Sines:
We need to find an equation that helps us solve for angle [tex]\( A \)[/tex]. Given the side [tex]\(a\)[/tex] and the angle [tex]\(C\)[/tex] opposite to side [tex]\(c\)[/tex], we get:
[tex]\[ \frac{\sin (A)}{2.4} = \frac{\sin (110^\circ)}{4.6} \][/tex]

4. Conclude with the correct equation:
The correct equation to use for solving angle [tex]\( A \)[/tex] is:
[tex]\[ \frac{\sin (A)}{2.4} = \frac{\sin (110^\circ)}{4.6} \][/tex]

Therefore, the equation that can be used to solve for angle [tex]\( A \)[/tex] is:
[tex]\[ \boxed{\frac{\sin (A)}{2.4} = \frac{\sin (110^\circ)}{4.6}} \][/tex]