To determine how many moles of iron (Fe) can be obtained when 1.75 moles of iron(II) oxide (FeO) reacts with an excess of carbon monoxide (CO), let's follow these steps:
1. Understand the balanced chemical equation:
The reaction is:
[tex]\[
\text{FeO} + \text{CO} \longrightarrow \text{Fe} + \text{CO}_2
\][/tex]
2. Identify the molar ratio:
From the balanced chemical equation, we can see that 1 mole of FeO reacts with 1 mole of CO to produce 1 mole of Fe and 1 mole of CO₂. The molar ratio of FeO to Fe is 1:1.
3. Calculate the moles of iron (Fe) produced:
Since the molar ratio of FeO to Fe is 1:1, the number of moles of Fe produced will be the same as the number of moles of FeO that reacted.
Given:
[tex]\[
\text{moles of FeO} = 1.75 \, \text{mol}
\][/tex]
Therefore, the moles of Fe produced will also be 1.75 mol.
Thus, when 1.75 moles of FeO reacts with an excess of CO, 1.75 moles of iron (Fe) can be obtained.
