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The table shows the distribution, by age, of a random sample of 3670 moviegoers ages 12-74. If one moviegoer is randomly selected from this population, find the probability, expressed as a simplified fraction, that the moviegoer's age is at least 25.

Age Distribution of Moviegoers
\begin{tabular}{|c|r|}
\hline
Ages & Number \\
\hline
[tex]$12-24$[/tex] & 1360 \\
\hline
[tex]$25-44$[/tex] & 1100 \\
\hline
[tex]$45-64$[/tex] & 690 \\
\hline
[tex]$65-74$[/tex] & 520 \\
\hline
\end{tabular}

The probability is [tex]$\square$[/tex] (Type an integer or a simplified fraction.)

Sagot :

To find the probability that a randomly selected moviegoer is at least 25 years old, follow these steps:

1. Determine the total number of moviegoers:
The total number of moviegoers is given as 3670.

2. Calculate the number of moviegoers aged 25 or older:
Sum the number of moviegoers in the age groups 25-44, 45-64, and 65-74:
[tex]\[ \text{Number of moviegoers aged 25 or older} = 1100 + 690 + 520 = 2310 \][/tex]

3. Set up the probability fraction:
The probability is the ratio of the number of moviegoers aged 25 or older to the total number of moviegoers:
[tex]\[ \text{Probability} = \frac{2310}{3670} \][/tex]

4. Simplify the fraction:
To simplify [tex]\(\frac{2310}{3670}\)[/tex], find the greatest common divisor (GCD) of 2310 and 3670. Here, the GCD is 10. Divide both the numerator and the denominator by the GCD to simplify the fraction:
[tex]\[ \frac{2310 \div 10}{3670 \div 10} = \frac{231}{367} \][/tex]

So, the probability that a randomly selected moviegoer is at least 25 years old, expressed as a simplified fraction, is:
[tex]\[ \boxed{\frac{231}{367}} \][/tex]
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