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What is the y-intercept of the line given by the equation below?

[tex]y = -10x + 14[/tex]

A. [tex]\(( -10, 0 )\)[/tex]
B. [tex]\(( 0, -10 )\)[/tex]
C. [tex]\(( 14, 0 )\)[/tex]
D. [tex]\(( 0, 14 )\)[/tex]

Sagot :

GinnyAnswer
To determine the y-intercept of the line given by the equation [tex]\( y = -10x + 14 \)[/tex], follow these steps:

1. Understand the y-intercept: The y-intercept is the point where the line crosses the y-axis. This occurs where [tex]\( x \)[/tex] is equal to 0.

2. Set [tex]\( x \)[/tex] to 0 in the equation: Substitute [tex]\( x = 0 \)[/tex] into the equation [tex]\( y = -10x + 14 \)[/tex].

[tex]\[ y = -10(0) + 14 \][/tex]

3. Calculate the value of [tex]\( y \)[/tex]:

[tex]\[ y = 0 + 14 \][/tex]

[tex]\[ y = 14 \][/tex]

4. Determine the y-intercept point: Since the y-intercept is where [tex]\( x = 0 \)[/tex], and we have found [tex]\( y = 14 \)[/tex], the y-intercept is the point [tex]\((0, 14)\)[/tex].

Thus, the y-intercept of the line [tex]\( y = -10x + 14 \)[/tex] is:

[tex]\[ \boxed{(0, 14)} \][/tex]
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