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Sagot :
To determine the power delivered to a light bulb when the circuit has a voltage of 120 volts (V) and produces a current of 0.5 amperes (A), you can use the formula for electrical power:
[tex]\[ P = V \times I \][/tex]
where:
- [tex]\( P \)[/tex] is the power in watts (W),
- [tex]\( V \)[/tex] is the voltage in volts (V),
- [tex]\( I \)[/tex] is the current in amperes (A).
Given:
- Voltage, [tex]\( V = 120 \)[/tex] volts,
- Current, [tex]\( I = 0.5 \)[/tex] amperes,
Substitute these values into the formula:
[tex]\[ P = 120 \, \text{V} \times 0.5 \, \text{A} \][/tex]
[tex]\[ P = 60 \, \text{W} \][/tex]
So, the power delivered to the light bulb is 60 watts. Therefore, the correct answer is:
[tex]\[ \text{60 watts} \][/tex]
[tex]\[ P = V \times I \][/tex]
where:
- [tex]\( P \)[/tex] is the power in watts (W),
- [tex]\( V \)[/tex] is the voltage in volts (V),
- [tex]\( I \)[/tex] is the current in amperes (A).
Given:
- Voltage, [tex]\( V = 120 \)[/tex] volts,
- Current, [tex]\( I = 0.5 \)[/tex] amperes,
Substitute these values into the formula:
[tex]\[ P = 120 \, \text{V} \times 0.5 \, \text{A} \][/tex]
[tex]\[ P = 60 \, \text{W} \][/tex]
So, the power delivered to the light bulb is 60 watts. Therefore, the correct answer is:
[tex]\[ \text{60 watts} \][/tex]
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