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If [tex]$x^2 + y^3 = 14$[/tex] and [tex]$xy = 5$[/tex], find the value of [tex]n[/tex] in [tex][tex]$(x+y)^3 = n$[/tex][/tex].

Sagot :

To solve the system of equations and find the value of [tex]\( n = (x + y)^3 \)[/tex], we need to follow these steps:

1. Define the equations:

[tex]\[ x^2 + y^3 = 14 \][/tex]
[tex]\[ xy = 5 \][/tex]

2. Solve the system of equations:

To find the possible values of [tex]\( x \)[/tex] and [tex]\( y \)[/tex], we use algebraic techniques to solve the system. However, it turns out that this system does not produce any real number solutions [tex]\((x, y)\)[/tex] that satisfy both equations simultaneously.

3. Determine [tex]\( (x + y)^3 \)[/tex]:

Since there are no [tex]\( x \)[/tex] and [tex]\( y \)[/tex] values that satisfy both given equations, the calculation of [tex]\( (x + y)^3 \)[/tex] can not proceed with any valid pairs of [tex]\( x \)[/tex] and [tex]\( y \)[/tex].

4. Conclusion:

Because no valid solutions for [tex]\( x \)[/tex] and [tex]\( y \)[/tex] exist, we conclude that there are no valid values for [tex]\( (x + y)^3 \)[/tex].

In conclusion, the value of [tex]\( n = (x + y)^3 \)[/tex] given the system of equations is:

[tex]\[ \boxed{[]} \][/tex]

There are no values of [tex]\( n \)[/tex] that satisfy the system of equations.
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